【LeetCode】929. Unique Email Addresses 解题报告（Python）

作者： 负雪明烛
id： fuxuemingzhu
个人博客： http://fuxuemingzhu.cn/

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题目地址：https://leetcode.com/problems/unique-email-addresses/description/

题目描述

Every email consists of a local name and a domain name, separated by the @ sign.

For example, in [email protected], alice is the local name, and leetcode.com is the domain name.

Besides lowercase letters, these emails may contain '.'s or '+'s.

If you add periods ('.') between some characters in the local name part of an email address, mail sent there will be forwarded to the same address without dots in the local name. For example, "[email protected]" and "[email protected]" forward to the same email address. (Note that this rule does not apply for domain names.)

If you add a plus ('+') in the local name, everything after the first plus sign will be ignored. This allows certain emails to be filtered, for example [email protected] will be forwarded to [email protected]. (Again, this rule does not apply for domain names.)

It is possible to use both of these rules at the same time.

Given a list of emails, we send one email to each address in the list. How many different addresses actually receive mails?

Example 1:

Input: ["[email protected]","[email protected]","[email protected]"]
Output: 2
Explanation: "[email protected]" and "[email protected]" actually receive mails

Note:

1. 1 <= emails[i].length <= 100
2. 1 <= emails.length <= 100
3. Each emails[i] contains exactly one ‘@’ character.

题目大意

判断有多少个不重复的email.

邮箱的规则是这样的：域名部分不用管，只管用户名部分，用户名中如果包含有'.'，那么把这个'.'给去掉；如果用户名中有'+'，那么把加号以及后面的用户名部分全部去掉。

解题方法

set + 字符串操作

Python处理这种字符串题目简直不要太简单，这个题是周赛第一题，用了6分钟读完题目，然后提交通过了。

首先把'.'给替换掉，然后查找是不是包含'+'，如果有的话，只保留其前面的部分就好了。

因为要去重，所以要使用一个set保存所有不重复的结果。

时间复杂度是O(N)，空间复杂度是O(N)。

class Solution(object):
    def numUniqueEmails(self, emails):
        """
        :type emails: List[str]
        :rtype: int
        """
        eset = set()
        for email in emails:
            simper = self.simpifyEmail(email)
            eset.add(simper)
        return len(eset)
    
    def simpifyEmail(self, email):
        local, domain = email.split("@")
        local = local.replace('.', '')
        plus_i = local.find('+')
        if plus_i != -1:
            local = local[:plus_i]
        return local + "@" + domain

代码可以优化变短，使用replace代替find函数。

class Solution:
    def numUniqueEmails(self, emails):
        """
        :type emails: List[str]
        :rtype: int
        """
        res = set()
        for email in emails:
            name, domain = email.split("@")
            name = name.split("+")[0].replace(".", "")
            res.add(name + "@" + domain)
        return len(res)

参考资料

日期

2018 年 10 月 28 日 —— 啊，悲伤的周赛