LuoguP5322 [BJOI2019]排兵布阵(DP)

城为物，人为容，价值？排序后，一切都明了

#include 
#include 
#include 
#include 
#include 
#include 
#define R(a,b,c) for(register int a = (b); a <= (c); ++a)
#define nR(a,b,c) for(register int a = (b); a >= (c); --a)
#define Fill(a,b) memset(a, b, sizeof(a))
#define Swap(a,b) ((a) ^= (b) ^= (a) ^= (b))
#define QWQ
#ifdef QWQ
#define D_e_Line printf("\n---------------\n")
#define D_e(x) cout << (#x) << " : " << x << "\n"
#define Pause() system("pause")
#define FileOpen() freopen("in.txt", "r", stdin)
#define FileSave() freopen("out.txt", "w", stdout)
#define TIME() fprintf(stderr, "\nTIME : %.3lfms\n", clock() * 1000.0 / CLOCKS_PER_SEC)
#else
#define D_e_Line ;
#define D_e(x) ;
#define Pause() ;
#define FileOpen() ;
#define FileSave() ;
#define TIME() ;
#endif
struct ios {
    template inline ios& operator >> (ATP &x) {
        x = 0; int f = 1; char c;
        for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-') f = -1;
        while(c >= '0' && c <='9') x = x * 10 + (c ^ '0'), c = getchar();
        x *= f;
        return *this;
    }
}io;
using namespace std;
template inline ATP Max(ATP a, ATP b) {
    return a > b ? a : b;
}
template inline ATP Min(ATP a, ATP b) {
    return a < b ? a : b;
}
template inline ATP Abs(ATP a) {
    return a < 0 ? -a : a;
}

const int N = 107;

int f[20007], a[N][N];

int main() {
    int s, n, m;
    io >> s >> n >> m;
    R(i,1,s){
        R(j,1,n){
            io >> a[j][i];
        }
    }
    R(i,1,n){
        sort(a[i] + 1, a[i] + s + 1);
    }
    R(i,1,n){
        nR(j,m,0){
            R(k,1,s){
                if(j >= (a[i][k] << 1 | 1)){
                    f[j] = Max(f[j], f[j - ((a[i][k] << 1 | 1))] + k * i);
                }
            }
        }
    }
    int ans = 0;
    R(i,0,m) ans = Max(ans, f[i]);
    printf("%d", ans);
    return 0;
}