用R计算理论塔板数_0.1

老板说要计算2700块踏板的精馏塔,手算不可能,得靠编程。于是先试着用R写了代码,来计算已有实例中的理论塔板数。经过几次修改,得到正确的结果。

已知条件:

  1. 泡点进料,所以q=1;
  2. xD=0.95,xF=0.40,xW=0.02;
  3. 平衡线方程:;
  4. 精馏段操作线方程:;
  5. 提馏段操作线方程:.

R代码:

x<-1
y<-0.95
n<-0
X<-c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)
Y<-X
while(x>=0.02){
  x<-y/(2.47-1.47*y);
  n<-n+1;
  X[n]<-x;
  Y[n]<-y;
  if(x>=0.4){
    y<-0.677*x+0.306;
    h<-n;
  }
  else{
    y<-1.467*x-0.009;
  }
}
cat("理论塔板数:",n,"\n","精馏段塔板数:",h,"\n","提留段塔板数:",n-h,"\n","进料板:",h+1)
##  理论塔板数: 15 
##  精馏段塔板数: 6 
##  提留段塔板数: 9 
##  进料板: 7
cat("各塔板气液组成:","\n",X,"\n",Y)
##  各塔板气液组成: 
##  0.885 0.7943 0.6862 0.5762 0.4811 0.4098 0.3619 0.3065 0.2418 0.1762 0.1186 0.07409 0.0429 0.02256 0.009898 
##  0.95 0.9051 0.8438 0.7705 0.6961 0.6317 0.5835 0.5219 0.4406 0.3457 0.2495 0.165 0.09968 0.05394 0.0241

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