字典数组结合

import

int main(int argc, const char * argv[]) {
@autoreleasepool {
NSArray *vegetable=@[@{@"name":@"芹菜",@"count":@"2",@"price":@"2.5"},@{@"name":@"口蘑",@"count":@"1.7",@"price":@"6"},@{@"name":@"红薯",@"count":@"3.2",@"price":@"1.5"}
];
double shishou=50;
NSString * name=@"";
double count=0;
double price=0;
double s=0;
double s1=0;
double sum=0;

    NSLog(@"名称   单价   数量   价格");
    for (NSDictionary *d in vegetable) {
        s=[d[@"count"]doubleValue]*[d[@"price"]doubleValue];
        name=d[@"name"];
        count=[d[@"count"]doubleValue];
        price=[d[@"price"]doubleValue];
        s1=s1+s;
        sum=50-s1;
       NSLog(@"%@   %.1lf   %.1lf   %.1lf",name,count,price,s);
    }

    NSLog(@"实收：%.1lf 应收：%.1lf 找零:%.1lf",shishou,s1,sum);
        }
return 0;

}