leetcode_twoSum

题目

LeetCode: two-sum

leetcode_twoSum_第1张图片
two-sum

暴力破解

/**
 * Note: The returned array must be malloced, assume caller calls free().
 */
int* twoSum(int* nums, int numsSize, int target) {
    int max = INT_MIN;
    int min = INT_MAX;
    int * indices = (int *) malloc(sizeof(int)*2);
    
    for (int i = 0; i < numsSize; ++i)
    {
        if (nums[i] > max) max = nums[i];
        if (nums[i] < min) min = nums[i];
    }
    int * map = (int *) calloc(max-min+1, sizeof(int));
    
    for (int i = 0; i < numsSize; ++i)
    {
        map[nums[i] - min] = i;
    }
    
    for (int i = 0; i < numsSize; ++i)
    {
        int lookfornum = target - nums[i];
        if (lookfornum < min || lookfornum > max) continue;
        if (map[lookfornum - min] != 0 && map[lookfornum - min] != i)
        {
            indices[0] = i;
            indices[1] = map[lookfornum - min];
            break;
        }
    }
    return indices;
}

你可能感兴趣的:(leetcode_twoSum)