获取iphone的系统信息使用[UIDevice currentDevice],信息如下:
[[UIDevice currentDevice] systemName]:系统名称,如iPhone OS
[[UIDevice currentDevice] systemVersion]:系统版本,如4.2.1
[[UIDevice currentDevice] model]:The model of the device,如iPhone或者iPod touch
[[UIDevice currentDevice] uniqueIdentifier]:设备的惟一标识号,deviceID
[[UIDevice currentDevice] name]:设备的名称,如 张三的iPhone
[[UIDevice currentDevice] localizedModel]:The model of the device as a localized string,类似model
详见http://developer.apple.com/library/ios/#documentation/uikit/reference/UIDevice_Class/Reference/UIDevice.html
但是以上的信息貌似无法得到设备的硬件信息,例如一个iphone3GS,系统升级到了iphone4。此时使用systemVersion得到的应该是4.x.x,那我们如何知道该设备为iphone3GS呢。网上流传一个方法,经测试应该是有用的。
自定义一个类:
#import
@interface UIDeviceHardware : NSObject {
}
- (NSString *) platform;
- (NSString *) platformString;
@end
#import "UIDeviceHardware.h"
#include
#include
@implementation UIDeviceHardware
- (NSString *) platform{
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *machine = malloc(size);
sysctlbyname("hw.machine", machine, &size, NULL, 0);
NSString *platform = [NSString stringWithCString:machine encoding:NSUTF8StringEncoding];
free(machine);
return platform;
}
- (NSString *) platformString{
NSString *platform = [self platform];
if ([platform isEqualToString:@"iPhone1,1"]) return @"iPhone 1G";
if ([platform isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
if ([platform isEqualToString:@"iPhone2,1"]) return @"iPhone 3GS";
if ([platform isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
if ([platform isEqualToString:@"iPod1,1"]) return @"iPod Touch 1G";
if ([platform isEqualToString:@"iPod2,1"]) return @"iPod Touch 2G";
if ([platform isEqualToString:@"iPod3,1"]) return @"iPod Touch 3G";
if ([platform isEqualToString:@"iPod4,1"]) return @"iPod Touch 4G";
if ([platform isEqualToString:@"iPad1,1"]) return @"iPad";
if ([platform isEqualToString:@"i386"] || [platform isEqualToString:@"x86_64"]) return @"iPhone Simulator";
return platform;
}
@end
使用[[[UIDeviceHardware alloc] init] platform]应该就可以得到设备的硬件版本