swift 数组

定义一个不可变数

let array : Array = ["lxd", "xiaoming", "xiaohong", "xiaogang"]

或者

let array1 : [String] =  ["lxd", "xiaoming", "xiaohong", "xiaogang"]```
let array2 = ["lxd", "xiaoming", "xiaohong", "xiaogang"]
let array3 : [Int] = [10, 20, 30]
let array4 : Array = ["lxd", "cc", 9.99]
let array5 : [Any] = [18, "why", 1.88]
let array6 = [18, "why", 1.88] as [Any]

定义可变数组

var names : [String] = ["lxd", "xiaoming", "xiaohong", "xiaogang"]

定义一个空数组

var names3 = [String]()
或者
var names1 : [String] = Array()
var names2 = Array()

可变数组
添加元素

names.append("xiaokai")
names.insert("lxd", at: 2)

删除数组

names.removeAll()
names.remove(at: 0)

修改元素

names[0] = "dd"

取出某个元素

names[2]
names.firstIndex(of: "xiaoming")
names.lastIndex(of: "xiaohong")

遍历数组

for i in 0..

指定区间遍历

for i in 0..<2 {
    print(names[i])
}

for item in names[0..<2] {
    print(item)
}

数组合并

//两个数组中存放的元素类型一致
let name4 = ["qq", "ww"]
var name5 = ["ee", "rr"]
let name6 = name4 + name5