ios 数组中相同属性值对象进行分组

说一下标题意思， 就是一个数组中很多对象，每个对象都有相同属性，然后，属性值也相等的 分别放到一个数组，怎么实现呢

。。。。。

方式一

- (void)sameArrayGroup
{
    MOBLabel *lab1 = [[MOBLabel alloc] init];
    lab1.name = @"2";
    MOBLabel *lab2 = [[MOBLabel alloc] init];
    lab2.name = @"3";
    MOBLabel *lab3 = [[MOBLabel alloc] init];
    lab3.name = @"2";
    MOBLabel *lab4 = [[MOBLabel alloc] init];
    lab4.name = @"0";
    MOBLabel *lab5 = [[MOBLabel alloc] init];
    lab5.name = @"0";
    
    
    
    NSArray *array2 = @[lab1, lab2, lab3, lab4, lab5];
    
    
    NSMutableArray *array = [NSMutableArray arrayWithArray:array2];
    NSMutableArray *dateMutablearray = [@[] mutableCopy];
    for (int i = 0; i < array.count; i ++) {

        MOBLabel *lab = array[i];

        NSMutableArray *tempArray = [@[] mutableCopy];

        [tempArray addObject:lab];
        NSLog(@"====0000======");

        for (int j = i+1; j < array.count; j ++) {

            MOBLabel *jlab = array[j];

            if([lab.name isEqualToString:jlab.name]){

                [tempArray addObject:lab];
                NSLog(@"====11====");
                [array removeObjectAtIndex:j];
                j -= 1;
            }
        }
        [dateMutablearray addObject:tempArray];
    }
    NSLog(@"dateMutable:%@",dateMutablearray);
}

结果

dateMutable:(
        (
        ">",
        ">"
    ),
        (
        ">"
    ),
        (
        ">",
        ">"
    )
)

方式二

NSArray *array1 = @[@"2016-10-01",@"2016-10-02",@"2016-10-03",
                        
                        @"2016-10-01",@"2016-10-02",@"2016-10-03",
                        
                        @"2016-10-01",@"2016-10-02",@"2016-10-03",
                        
                        @"2016-10-01",@"2016-10-02",@"2016-10-03",
                        
                        @"2016-10-01",@"2016-10-02",@"2016-10-03",
                        
                        @"2016-10-01",@"2016-10-02",@"2016-10-03",
                        
                        @"2016-10-04",@"2016-10-06",@"2016-10-08",
                        
                        @"2016-10-05",@"2016-10-07",@"2016-10-09"];
    
    //NSArray *array2 = @[lab1, lab2, lab3, lab4, lab5];
    
    NSMutableArray *array = [NSMutableArray arrayWithArray:array1];
    
    NSMutableArray *dateMutablearray = [@[] mutableCopy];
    for (int i = 0; i < array.count; i ++) {
        
        NSString *string = array[i];
        
        NSMutableArray *tempArray = [@[] mutableCopy];
        
        [tempArray addObject:string];
        
        for (int j = i+1; j < array.count; j ++) {
            
            NSString *jstring = array[j];
            
            if([string isEqualToString:jstring]){
                
                [tempArray addObject:jstring];
                
                [array removeObjectAtIndex:j];
                j -= 1;
                
            }
            
        }
        
        [dateMutablearray addObject:tempArray];
        
    }
    
    NSLog(@"dateMutable:%@",dateMutablearray);
结果
2018-04-12 15:38:08.641319+0800 MOBTestVC[11909:323618] dateMutable:(
        (
        "2016-10-01",
        "2016-10-01",
        "2016-10-01",
        "2016-10-01",
        "2016-10-01",
        "2016-10-01"
    ),
        (
        "2016-10-02",
        "2016-10-02",
        "2016-10-02",
        "2016-10-02",
        "2016-10-02",
        "2016-10-02"
    ),
        (
        "2016-10-03",
        "2016-10-03",
        "2016-10-03",
        "2016-10-03",
        "2016-10-03",
        "2016-10-03"
    ),
        (
        "2016-10-04"
    ),
        (
        "2016-10-06"
    ),
        (
        "2016-10-08"
    ),
        (
        "2016-10-05"
    ),
        (
        "2016-10-07"
    ),
        (
        "2016-10-09"
    )
)

比较简洁的方式======================

MOBLabel *lab1 = [[MOBLabel alloc] init];
    lab1.name = @"2";
    MOBLabel *lab2 = [[MOBLabel alloc] init];
    lab2.name = @"3";
    MOBLabel *lab3 = [[MOBLabel alloc] init];
    lab3.name = @"2";
    MOBLabel *lab4 = [[MOBLabel alloc] init];
    lab4.name = @"0";
    MOBLabel *lab5 = [[MOBLabel alloc] init];
    lab5.name = @"0";
    
    
    
    NSArray *array2 = @[lab1, lab2, lab3, lab4, lab5];
    
    NSMutableDictionary *res = @{}.mutableCopy;

    for (MOBLabel *obj in array2)
    {
        if (res[obj.name])
        {
            [res[obj.name] addObject:obj];
        }
        else
        {
            res[obj.name] = [NSMutableArray arrayWithObject:obj];
        }
    }

    NSLog(@"-----%@",res.allValues);

结果
 -----(
        (
        ">",
        ">"
    ),
        (
        ">"
    ),
        (
        ">",
        ">"
    )
)

```