400. Nth Digit

Find the nth digit of the infinite integer sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...
Note:
n is positive and will fit within the range of a 32-bit signed integer (n < 231).

Example 1:
Input:
3
Output:
3

Example 2:
Input:
11
Output:
0

Explanation:
The 11th digit of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ... is a 0, which is part of the number 10.

Solution：

思路：
Straight forward way to solve the problem in 3 steps:

find the length of the number where the nth digit is from
find the actual number where the nth digit is from
find the nth digit and return

Time Complexity: O(N) Space Complexity: O(1)

Solution Code：

class Solution {
    public int findNthDigit(int n) {
        int len = 1;
        long count = 9;
        int start = 1;

        while (n > len * count) {
            n -= len * count;
            len += 1;
            count *= 10;
            start *= 10;
        }

        start += (n - 1) / len;
        String s = Integer.toString(start);
        return Character.getNumericValue(s.charAt((n - 1) % len));
    }
}