情况:v2 namespace需要访问default namespace的rabbitmq服务
解决办法:在v2 namespace里面创建service,不指定selector, 采用type=ExternalName的方式,externalName定义成为指向namespace=default中的rabbitmq-service
# vi rabbitmq.yaml
apiVersion: v1
kind: Service
metadata:
name: rabbitmq
namespace: v2
spec:
ports:
- port: 5672
name: amqp
sessionAffinity: None
type: ExternalName
externalName: rabbitmq.default.svc.cluster.local
[root@bdy-master1]# kubectl create -f rabbitmq.yaml
[root@bdy-master1]# kubectl get service -A |grep rabbit
default rabbitmq ClusterIP None
default rabbitmq-service NodePort 10.254.252.174
v2 rabbitmq ExternalName
测试是否可以跨namespace访问
[root@bdy-master1 rabbitmq-service]# kubectl exec -it -n v2 api-57596df5b8-sx2hc sh
/var/www/html # nslookup rabbitmq
nslookup: can't resolve '(null)': Name does not resolve
Name: rabbitmq
Address 1: 172.30.28.24 172-30-28-24.rabbitmq.default.svc.cluster.local
Address 2: 172.30.3.4 rabbitmq-1.rabbitmq.default.svc.cluster.local
Address 3: 172.30.43.8 172-30-43-8.rabbitmq.default.svc.cluster.local
Address 4: 172.30.43.2 rabbitmq-2.rabbitmq.default.svc.cluster.local
Address 5: 172.30.3.30 172-30-3-30.rabbitmq.default.svc.cluster.local
Address 6: 172.30.28.2 rabbitmq-0.rabbitmq.default.svc.cluster.local
/var/www/html # ping rabbitmq
PING rabbitmq (172.30.43.2): 56 data bytes
64 bytes from 172.30.43.2: seq=0 ttl=62 time=0.720 ms
64 bytes from 172.30.43.2: seq=1 ttl=62 time=0.650 ms
^C
--- rabbitmq ping statistics ---
2 packets transmitted, 2 packets received, 0% packet loss
round-trip min/avg/max = 0.650/0.685/0.720 ms
/var/www/html # nc -n -v rabbitmq 5672
rabbitmq (172.30.43.2:5672) open
^[[A^Cpunt!