[python] 判断密码强度

网站记录：https://py.checkio.org/mission/house-password/solve/

问题：判读输入的密码是否符合要求：超过10位，英文加数字，大小写，没有特殊符号

我的代码：

import re

def checklen(data):
    return len(data) >= 10

def checkUpper(data):
    upper = re.compile('[A-Z]+')
    match = upper.findall(data)
    if match:
        return True
    else:
        return False

def checkLower(data):
    lower = re.compile('[a-z]+')
    match = lower.findall(data)
    if match:
        return True
    else:
        return False

def checkNum(data):
    num = re.compile('[0-9]+')
    match = num.findall(data)
    if match:
        return True
    else:
        return False

def checkSymbol(data):
    symbol = re.compile('([^a-zA-Z0-9])+')
    match = symbol.findall(data)
    if match:
        return True
    else:
        return False

def checkio(data):
    if checklen(data):
        if checkUpper(data):
            if checkLower(data):
                if checkNum(data):
                    return True
                else:
                    return False
            else:
                return False
        else:
            return False
    else:
        return False
    
if __name__ == '__main__':

大神的代码：（代码来自：https://py.checkio.org/mission/house-password/publications/Renelvon/python-3/first/?ordering=most_voted&filtering=choice   作者：Renelvon）

def checkio(s):
    fs = ''.join(filter(str.isalnum, s)) # keep only letters and digits
    return (
            len(fs) >= 1        # There is at least one letter or digit
        and len(s)  >= 10       # ... and there are at least 10 characters
        and not fs.isalpha()    # ... and there is at least one digit
        and not fs.isdigit()    # ... and there is at least one letter
        and not fs.islower()    # ... and not all letters are lowercase
        and not fs.isupper()    # ... and not all letters are uppercase
    )

大神二（Riddick）

import re
def checkio(data):
    return True if re.search("^(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).*$", data) and len(data) >= 10 else False


if __name__ == '__main__':