[LeetCode34]Search for a Range

Given a sorted array of integers, find the starting and ending position of a given target value.

Your algorithm's runtime complexity must be in the order of O(log n).

If the target is not found in the array, return [-1, -1].

For example,
Given [5, 7, 7, 8, 8, 10] and target value 8,

return [3, 4].

Analysis:

From the question, we may know it need binary search. 

The idea is to search twince one for left range bound, one for right range bound. 

Java

public int[] searchRange(int[] A, int target) {
        int[] result = new int[2];
        result[0] = getBoundRange(A, 0, A.length-1, target, true);
        result[1] = getBoundRange(A, 0, A.length-1, target, false);
        return result;
    }
	public int getBoundRange(int[]A, int l, int r, int target, boolean left){
		if(l>r) return -1;
		else{
		int m = (l+r)/2;
		if(A[m]==target){
			if(left){
				if(m==0 || A[m-1]target) {
			return getBoundRange(A, l, m-1, target, left);
		}else {
			return getBoundRange(A, m+1, r, target, left);
		}
		}
	}

Another solution:

public int[] searchRange(int[] A, int target) {
        int[] result = new int[2];
        result[0] = -1;
        result[1] = -1;
        if(A[0]>target || A[A.length-1]=0&&A[low]==target){
        			low--;
        		}
        		result[0]=low+1;
        		while(hightarget){
        		high = mid-1;
        	}else {
				low = mid+1;
			}
        }
        return result;
    }

c++

int searchTarget(int A[], int start, int end, int target){
    if(start > end)
        return -1;
    else{
        int mid = (start+end)/2;
        if(A[mid] == target) return mid;
        if(A[mid]> target)
            return searchTarget(A,start,mid-1,target);
        if(A[mid] searchRange(int A[], int n, int target) {
    vector result;
    int index = searchTarget(A,0,n-1,target);
    if(index == -1){
        result.push_back(-1);
        result.push_back(-1);
        return result;
    }
    else{
        int ls = index;
        while(ls>0 && A[index] == A[ls-1]) ls--;
        int rs = index;
        while(rs