Python获取高德地图POI信息

** ** 朋友需要帮忙获取资源信息，于是我利用周末时间，用python写了个工具从高德地图上抓取信息（包括位置，电话，经纬度等），得到了他想要的数据, 绝对可靠****

 url = "http://restapi.amap.com/v3/place/text?&keywords=&types=" + self.cityType + "&city=" + self.cityID + "&citylimit=true&output=xml&offset=" + str(offset) + "&page="+ str(maxPage) + "&key=你的key&extensions=base"

        if self.getHtml(url)==0:
            print 'parsing page 1 ... ...'
            #parse the xml file and get the total record number
            totalRecord_str=self.parseXML()
     
            totalRecord=string.atoi(str(totalRecord_str))
            if (total_record%offset)!=0:
                maxPage=totalRecord/offset+2
            else:
                maxPage=totalRecord/offset+1

            print(totalRecord)
            print(maxPage)

        for pageIndex in range(1, maxPage + 1):
            try:
                url = "http://restapi.amap.com/v3/place/text?&keywords=&types=" + self.cityType + "&city=" + self.cityID + "&citylimit=true&output=xml&offset=" + str(offset) + "&page="+ str(pageIndex) + "&key=你的key&extensions=base"
                # 请求的结构化url地址如上；请使用自己的key，见：http://lbs.amap.com/api/webservice/guide/api/search/
                poiSoup = BeautifulSoup(urllib.urlopen(url).read(),"xml") #读入对应页码的页面
                for tagIndex in range(len(poiTag)):
                    poiSoupTag[tagIndex] = poiSoup.findAll(poiTag[tagIndex]) # 根据Tag读对应页码的POI标签内容

                for rowIndex in range(len(poiSoupTag[0])):
                    for colIndex in range(len(poiSoupTag)):
                        sheet.write(len(poiSoupTag[0]) * (pageIndex - 1) + rowIndex + 1, colIndex, re.findall(pattern,u" "+str(poiSoupTag[colIndex][rowIndex])))
                        # 根据正则表达式提取内容，并在对应行与列写入
            except Exception as e:
                print(e) # 设置错误输出

        poiExcel.save("E:/POI&" + self.cityType + "&" + self.cityID + ".xls") # 保存

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