c语言练习题:求1-1/2+1/3-1/4+... -1/100的值

/*******************************************

    求1-1/2+1/3-1/4+... -1/100的值

*******************************************/
#include 

int main(void)
{
    int i = 1;
    float sum = 0;

    while(i <= 100)
    {
        if(i % 2 == 0)
        {
            sum -=1/(i++*1.0);
        }else
        {
            sum +=1/(i++*1.0);
        }
    }
    printf("%f\n",sum);
}

 

转载于:https://www.cnblogs.com/passedbylove/p/9016398.html