对哈姆雷特进行词频统计

def getText():
    txt = open("C:/Users/Administrator/Desktop/python-lianxi/hamlet.txt", "r").read()
    txt = txt.lower()   #首先把所有字母都转换成小写字母
    for ch in  '!"#$%()*+,-./:;<=>?@[\\]^_{|}·~‘’':   #排除掉英文字符，用空格替换
        txt = txt.replace(ch, " ")

    return txt

hamletTxt = getText()
words = hamletTxt.split()   #通过split函数用空格进行拆分
counts = {}
for word in words:
    counts[word] = counts.get(word,0) + 1   #字典的get方法，查找是否有键word,有则返回其对应键值，没有则返回后面的值0
items = list(counts.items())
items.sort(key=lambda x:x[1], reverse=True)  #列表的排序常用搭配，将元素的下标为第一个的元素作为关键字按照从大到小排序
for i in range(10):
    word,count = items[i]
    print("{0:<10}{1:>5}".format(word, count))