《Python语言程序设计基础》嵩天著-第4章程序部分练习题答案

《Python语言程序设计基础》嵩天著-第4章程序部分练习题答案

Python课上的作业。
贴到这里，供大家参考哦~
欢迎交流指正，共同进步，欸嘿！
没有把全部练习题写完，仅写了要求的作业。
至于运行结果，大家可以自己去试试

4.1 猜数游戏

# programp practice 4.1 猜数游戏
a = 8
i = 1
while 1:
    b = eval(input("   please guess a number bewteen\
\r 0 and 9 that i am thinking and enter a n* : "))
    if b < a :
        print("  what a pity! it is too small!")
        i = i+1
    elif b > a:
        print("  what a pity! it is too large")
        i = i+1
    else:
        print(" now you are right after {} times".format(i))
        break

4.2 统计不同字符个数

# programp practice 4.2 统计不同字符个数 
strs = input(" please enter anything you want: ")
a,b,c,d = 0,0,0,0 
for i in strs:
    if "0" <= i <= "9": # 判断数字
        a += 1
    elif i ==" " : # 判断空格
        b += 1
    elif "a" <= i <= "z" or "A" <= i <= "Z" : # 判断英文字符 
        c += 1
    else: # 判断其他字符 会把中文加到这里来
        d += 1
print("English characters have {},\n numbers have {},\
\n spaces have {},\n characters have {}".format(c,a,b,d))

4.2 的做法的不同表达方式~

# programp practice 4.2 统计不同字符个数 ，用unicode 与上面的本质一样
c,n,b,o = 0,0,0,0  # c代表字符个数 n代表数字个数 b代表空格个数 o代表其他字符个数
strs = input("please enter anything you want：")
for s in strs:
    if ord('a') <= ord(s) <= ord('z') or ord('A') <= ord(s) <= ord('Z'):
        c += 1
    elif ord('0') <= ord(s) <= ord('9'):
        n += 1
    elif ord(' ') == ord(s):
        b += 1
    else:
        o += 1
print("English word{0}个，number{1}个，space{2}个，other words{3}个".format(c,n,b,o))

4.4 猜数游戏续1

# programp practice 4.4 猜数游戏续1
import random as r
a = r.randint(0,100)
b = eval(input("please enter a n* between 0 and 100 : "))
i = 1
while b != a :
    i += 1
    if b < a :
        print("whta a pity! it is too small!")
    elif b > a:
        print("what a pity! it is too large")
    else:
        print("now you are right after {} times".format(i))
    b = eval(input("please enter a n* between 0 and 100 : "))
else:
    print("you toally entered {} times and the num is {}".format(i,b))

4.5 猜数游戏续2

# programp practice 4.5 猜数字续2 - 成功例子
import random as r
num = r.randint(0,100)
i = 0
while 1 :
    b = input("please enter a numbers bewteen 0 and 100 : ")
    i += 1
    if b.isdigit() : #判断字符串b是否为整数 isinstance(a,int)
        b = eval(b)
        if b < num :
            print("sorry! it is too small!")
        elif b > num :
            print("sorry! it is too large!")
        else:
            print("u entered {} times and the number is {}".format(i,b))
            break
    else:
        print("u must enter a n* !")

4.7 用异常处理改造实例1 方法一

# programp practice 4.7 用异常处理改造实例1-循环直至正确输出
while 1 :
    try:
        tem = input("please enter temperature in N* with unit :") 
        if tem[:-1].isnumeric() : # 只能处理整数的温度
            if tem[-1] in ["f","F"]:
                C = (eval(tem[:-1]) - 32)/1.8
                print('the  result is {:.2f}C'.format(C))
            elif tem[-1] in ['C','c']:
                F = 1.8 * (eval(tem[:-1])) + 32
                print('the  result is {:.2f}F'.format(F))
            break
        else:
            print("the content u entered is wrong")
    except:
        print("the format u entered is wrong")

4.7 用异常处理改造实例1 方法2

上一个4.7 的做法只能处理整数，
下面这个可以处理小数哦

# programp practice 4.7 用异常处理改造实例1-循环直至正确输出
while 1 :
    try: # 可处理小数的温度输入
        tem = input("please enter  temperature in N* with unit: ") 
        if tem[-1] in ["f","F"]:
            C = (eval(tem[:-1]) - 32)/1.8
            print('the  result is {:.2f}C'.format(C))
            break # 跳出循环
        elif tem[-1] in ['C','c']:
            F = 1.8 * (eval(tem[:-1])) + 32
            print('the  result is {:.2f}F'.format(F))
            break # 跳出循环
        else:
            print("the content u entered is wrong")
    except:
        print("the format u entered is wrong")

就这样叭，码字不易，太难了