【LeetCode】561. Array Partition 1（javascript版）

561.Array Partition 1

Given an array of 2n integers, your task is to group these integers
 into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) 
which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:

Input: [1,4,3,2]

Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).

Note:

n is a positive integer, which is in the range of [1, 10000].
All the integers in the array will be in the range of [-10000, 10000].

题目：数组拆分 1

给定长度为2n的数组，你的任务是将这些数组分成n对，例如(a1,b1),(a2,b2) ... (an,bn),使得从1到n的min(ai,bi)总和最大。

解题思路：先将数据排序，，然后间隔为2遍历数组，和相加即为最小值。

/**
 * @param {number[]} nums
 * @return {number}
 */
var arrayPairSum = function(nums) {
   const arrSorting =  nums.sort((a,b) => {return a-b});
    let sum = 0;
    for(i=0; i