dijkstra和dijkstra堆优化模板
之前QAQ一直没有准备堆优化模板,本例以PAT A1003为例,整理dijkstra和dijkstra堆优化模板
Dijkstra
我们可以发现该篇幅找最小值部分是使用量一个for循环
#include
#include
using namespace std;
int n, m, c1, c2;
int edge[510][510], weight[510], dis[510], num[510], w[510];
bool vis[510];
const int inf = 99999999;
int main() {
scanf("%d%d%d%d", &n, &m, &c1, &c2);
for(int i = 0; i < n; i++)
scanf("%d", &weight[i]);
fill(edge[0], edge[0] + 510 * 510, inf);
fill(dis, dis + 510, inf);
int a, b, c;
for(int i = 0; i < m; i++){
scanf("%d%d%d", &a, &b, &c);
edge[a][b] = edge[b][a] = c;
}
dis[c1] = 0;
w[c1] = weight[c1];
num[c1] = 1;
while(true) {
int u = -1, minn = inf;
for(int j = 0; j < n; j++){
if(vis[j] == false && dis[j] < minn) {
u = j;
minn = dis[j];
}
}
if(u == -1) break;
vis[u] = true;
for(int v = 0; v < n; v++) {
if(vis[v] == false && edge[u][v] != inf) {
if(dis[u] + edge[u][v] < dis[v]) {
dis[v] = dis[u] + edge[u][v];
num[v] = num[u];
w[v] = w[u] + weight[v];
}else if(dis[u] + edge[u][v] == dis[v]) {
num[v] = num[v] + num[u];
if(w[u] + weight[v] > w[v])
w[v] = w[u] + weight[v];
}
}
}
}
printf("%d %d", num[c2], w[c2]);
return 0;
}
dijkstra堆优化
我们在找最小值那部分进行替换成堆即可
#include
#include
#include
using namespace std;
int n, m, c1, c2;
int edge[510][510], weight[510], dis[510], num[510], w[510];
bool vis[510];
const int inf = 99999999;
priority_queue, vector>, greater>> q;
int main() {
scanf("%d%d%d%d", &n, &m, &c1, &c2);
for(int i = 0; i < n; i++)
scanf("%d", &weight[i]);
fill(edge[0], edge[0] + 510 * 510, inf);
fill(dis, dis + 510, inf);
int a, b, c;
for(int i = 0; i < m; i++){
scanf("%d%d%d", &a, &b, &c);
edge[a][b] = edge[b][a] = c;
}
dis[c1] = 0;
w[c1] = weight[c1];
num[c1] = 1;
q.push({0, c1});
while(q.size()) {
// 改为了弹出
int u = q.top().second;
q.pop();
// 如果已经访问,这边记得进行continue操作
if(vis[u]) continue;
vis[u] = true;
for(int v = 0; v < n; v++) {
if(vis[v] == false && edge[u][v] != inf) {
if(dis[u] + edge[u][v] < dis[v]) {
dis[v] = dis[u] + edge[u][v];
num[v] = num[u];
w[v] = w[u] + weight[v];
}else if(dis[u] + edge[u][v] == dis[v]) {
num[v] = num[v] + num[u];
if(w[u] + weight[v] > w[v])
w[v] = w[u] + weight[v];
}
q.push({dis[v], v});
}
}
}
printf("%d %d", num[c2], w[c2]);
return 0;
}