Golang Leetcode 226. Invert Binary Tree.go

思路

传说中的反转二叉树，递归交换

code

type TreeNode struct {
	Val   int
	Left  *TreeNode
	Right *TreeNode
}

func invertTree(root *TreeNode) *TreeNode {

	if root == nil {
		return root
	}
	root.Left = invertTree(root.Left)
	root.Right = invertTree(root.Right)
	root.Left, root.Right = root.Right, root.Left
	return root
}

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