JNI DETECTED ERROR IN APPLICATION: input is not valid Modified UTF-8: illegal start byte 0xfe
在使用Jni的JNIEnv->NewStringUTF的时候抛出了异常"JNI DETECTED ERROR IN APPLICATION: input is not valid Modified UTF-8: illegal start byte 0xfe "。网上搜索了一下，这个异常是由于Java虚拟机内部的dalvik/vm/CheckJni.c中的checkUtfString函数抛出的，并且JVM的这个接口明确是不支持四个字节的UTF8字符。因此需要在调用函数之前，对接口传入的字符串进行过滤，过滤函数如下：
int checkUtfString(const char* bytes) { const char* origBytes = bytes; if (bytes == NULL) { return -1; } while (*bytes != '\0') { unsigned char utf8 = *(bytes++); // Switch on the high four bits. switch (utf8 >> 4) { case 0x00: case 0x01: case 0x02: case 0x03: case 0x04: case 0x05: case 0x06: case 0x07: { // Bit pattern 0xxx. No need for any extra bytes. break; } case 0x08: case 0x09: case 0x0a: case 0x0b: case 0x0f: { /*printf("****JNI WARNING: illegal start byte 0x%x\n", utf8);*/ return -1; } case 0x0e: { // Bit pattern 1110, so there are two additional bytes. utf8 = *(bytes++); if ((utf8 & 0xc0) != 0x80) { /*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/ return -1; } // Fall through to take care of the final byte. } case 0x0c: case 0x0d: { // Bit pattern 110x, so there is one additional byte. utf8 = *(bytes++); if ((utf8 & 0xc0) != 0x80) { /*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/ return -1; } break; } } } return 0; }
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
|
int checkUtfString(const char* bytes)
{
const char* origBytes = bytes;
if (bytes == NULL) {
return -1;
}
while (*bytes != '\0') {
unsigned char utf8 = *(bytes++);
// Switch on the high four bits.
switch (utf8 >> 4) {
case 0x00:
case 0x01:
case 0x02:
case 0x03:
case 0x04:
case 0x05:
case 0x06:
case 0x07: {
// Bit pattern 0xxx. No need for any extra bytes.
break;
}
case 0x08:
case 0x09:
case 0x0a:
case 0x0b:
case 0x0f: {
/*printf("****JNI WARNING: illegal start byte 0x%x\n", utf8);*/
return -1;
}
case 0x0e: {
// Bit pattern 1110, so there are two additional bytes.
utf8 = *(bytes++);
if ((utf8 & 0xc0) != 0x80) {
/*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/
return -1;
}
// Fall through to take care of the final byte.
}
case 0x0c:
case 0x0d: {
// Bit pattern 110x, so there is one additional byte.
utf8 = *(bytes++);
if ((utf8 & 0xc0) != 0x80) {
/*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/
return -1;
}
break;
}
}
}
return 0;
}
|
参考链接 android jni中 utf-8的check
发布者
默默
newStringUTF出现input is not valid Modified UTF-8错误解决办法
2013年10月12日 ⁄ 综合 ⁄ 共 883字 ⁄ 字号 小 中 大 ⁄ 评论关闭
JNI调用newStringUTF时遇到不认识的字符串就直接出错退出~~,网上原因是dalvik/vm/CheckJni.c里面的checkUtfString函数检查通不过.找了半天没找到修正办法,把这个函数改了下,当做一个修正函数,下面是代码
void correctUtfBytes(char* bytes) {
char three = 0;
while (*bytes != '\0') {
unsigned char utf8 = *(bytes++);
three = 0;
// Switch on the high four bits.
switch (utf8 >> 4) {
case 0x00:
case 0x01:
case 0x02:
case 0x03:
case 0x04:
case 0x05:
case 0x06:
case 0x07:
// Bit pattern 0xxx. No need for any extra bytes.
break;
case 0x08:
case 0x09:
case 0x0a:
case 0x0b:
case 0x0f:
/*
* Bit pattern 10xx or 1111, which are illegal start bytes.
* Note: 1111 is valid for normal UTF-8, but not the
* modified UTF-8 used here.
*/
*(bytes-1) = '?';
break;
case 0x0e:
// Bit pattern 1110, so there are two additional bytes.
utf8 = *(bytes++);
if ((utf8 & 0xc0) != 0x80) {
--bytes;
*(bytes-1) = '?';
break;
}
three = 1;
// Fall through to take care of the final byte.
case 0x0c:
case 0x0d:
// Bit pattern 110x, so there is one additional byte.
utf8 = *(bytes++);
if ((utf8 & 0xc0) != 0x80) {
--bytes;
if(three)--bytes;
*(bytes-1)='?';
}
break;
}
}
}
http://www.xuebuyuan.com/1240531.html
http://www.mobibrw.com/2016/2859