python3.6之前 OrderedDict类(有序字典)

最新在学习一些知识用到有序字典,看到别人使用OrderedDict()。但查阅资料发现,python3.6(包含)之后,所有的普通dict()字典都变为有序的了,不再需要OrderedDict()这个类了。如果你还是使用python2,或python3.5之前的版本,那可以继续浏览下,否者就没必须看了。

文章目录

      • 1.创建有序字典
      • 2.clear(清空有序字典)
      • 3.copy(拷贝)
      • 4.fromkeys(指定一个列表,把列表中的值作为字典的key,生成一个字典)
      • 5.items(返回由“键值对组成元素“的列表)
      • 6.keys(获取字典所有的key)
      • 7.move_to_end(指定一个key,把对应的key-value移到最后)
      • 8.pop(获取指定key的value,并在字典中删除)
      • 9.popitem(按照后进先出原则,删除最后加入的元素,返回key-value)
      • 10.setdefault(获取指定key的value,如果key不存在,则创建)
      • 11.values(获取字典所有的value,返回一个列表)

1.创建有序字典

所谓有序字典,就是插入键值对的顺序,是按照你插入的顺序来排列的。字典不会因为key或value的值,再自动排序!!

import collections

dic = collections.OrderedDict()
dic['k3'] = 'v3'
dic['k1'] = 'v1'
dic['k2'] = 'v2'

print(dic)

#输出:OrderedDict([('k3', 'v3'), ('k1', 'v1'), ('k2', 'v2')])

2.clear(清空有序字典)

import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic.clear()
print(dic)

#输出:OrderedDict()

3.copy(拷贝)

import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
new_dic = dic.copy()
print(new_dic)

#输出:OrderedDict([('k1', 'v1'), ('k2', 'v2')])

4.fromkeys(指定一个列表,把列表中的值作为字典的key,生成一个字典)

import collections

dic = collections.OrderedDict()
name = ['tom','lucy','sam']
print(dic.fromkeys(name))
print(dic.fromkeys(name,20))

#输出:OrderedDict([('tom', None), ('lucy', None), ('sam', None)])
#     OrderedDict([('tom', 20), ('lucy', 20), ('sam', 20)])

5.items(返回由“键值对组成元素“的列表)

import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
print(dic.items())

#输出:odict_items([('k1', 'v1'), ('k2', 'v2')])

6.keys(获取字典所有的key)

import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
print(dic.keys())

# 输出:odict_keys(['k1', 'k2'])

7.move_to_end(指定一个key,把对应的key-value移到最后)

import collections
import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
dic.move_to_end('k1')
print(dic)

# 输出:OrderedDict([('k2', 'v2'), ('k3', 'v3'), ('k1', 'v1')])

8.pop(获取指定key的value,并在字典中删除)

import collections
import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
k = dic.pop('k2')
print(k,dic)

# 输出:v2 OrderedDict([('k1', 'v1'), ('k3', 'v3')])

9.popitem(按照后进先出原则,删除最后加入的元素,返回key-value)

import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
print(dic.popitem(),dic)
print(dic.popitem(),dic)

# 输出:('k3', 'v3') OrderedDict([('k1', 'v1'), ('k2', 'v2')])
#      ('k2', 'v2') OrderedDict([('k1', 'v1')])

10.setdefault(获取指定key的value,如果key不存在,则创建)

import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
val = dic.setdefault('k5')
print(val,dic)

# 输出:None OrderedDict([('k1', 'v1'), ('k2', 'v2'), ('k3', 'v3'), ('k5', None)])

11.values(获取字典所有的value,返回一个列表)

import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
print(dic.values())

# 输出:odict_values(['v1', 'v2', 'v3'])

文章来源:
https://www.cnblogs.com/zhenwei66/p/6596248.html

你可能感兴趣的:(Python基础)