使用xmlhttp.send()方法的参数来传递大容量的数据

使用xmlhttp.send()方法的参数来传递大容量的数据
Posted on 2009-01-12 16:31 MARTIALIS 阅读(624) 评论(0) 编辑 收藏 所属分类: ASP.NET
Ajax技术中的xmlhttp.send()方法提供我们传送大量数据的功能,要使用该功能,首先要将要传到服务端的数据封装在一个xml对象中,在将这个xml对象的xml属性做为send()方法的参数就可以.
客户端代码:
var guidArray = guidlist.split( " , " );
var xmlDom = new ActiveXObject( " MSXML2.DOMDocument " );
xmlDom.loadXML( "" );
var domRoot = xmlDom.createElement_x( " NewDataSet " );
xmlDom.appendChild(domRoot);
for ( var i = 0 ;i < guidArray.length;i )
{
var node = xmlDom.createElement_x( " guid " );
node.text = guidArray[i];
domRoot.appendChild(node);
}

var xmlhttp = new ActiveXObject( " MSXML2.XMLHTTP " );
xmlhttp.onreadystatechange = function (){
if (xmlhttp.readyState == 4 )
{
if (xmlhttp.status == 200 )
{
alert( " 处理完成 " );
}
else
{
alert(xmlhttp.responseText);
}
}

}
xmlhttp.Open( " POST " , " fmSmsPostProcess.aspx?sStatus= " escape(sStatus) " &sProcessResult= " escape(document.getElementByIdx_x( " btProcessResult " ).value)
" &sReStore= " escape(document.getElementByIdx_x( " btReStore " ).value), true );
xmlhttp.setRequestHeader( " Content-Type " , " text/xml " );
xmlhttp.send(xmlDom.xml);
服务端需要从请求流中,解析出客户端传入的xml的内容,服务端代码:
System.IO.Stream instream = Page.Request.InputStream;
BinaryReader br = new BinaryReader(instream,System.Text.Encoding.UTF8);
byte[] byt = br.ReadBytes((int)instream.Length);
string sXml = System.Text.Encoding.UTF8.GetString(byt);

System.Xml.XmlDocument xmlDoc = new System.Xml.XmlDocument();
xmlDoc.LoadXml(sXml);

XmlElement xe= xmlDoc.DocumentElement;
for(int i=0;i< xe.ChildNodes.Count;i )
{
sGuid = sGuid ",'" xe.ChildNodes[i].InnerText "'";
}