Codeforces Round #499 (Div. 2) 1011 A. Stages
A. Stages
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output
Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages.
There are nn stages available. The rocket must contain exactly kk of them. Stages in the rocket should be ordered by their weight. So, after the stage with some letter can go only stage with a letter, which is at least two positions after in the alphabet (skipping one letter in between, or even more). For example, after letter 'c' can't go letters 'a', 'b', 'c' and 'd', but can go letters 'e', 'f', ..., 'z'.
For the rocket to fly as far as possible, its weight should be minimal. The weight of the rocket is equal to the sum of the weights of its stages. The weight of the stage is the number of its letter in the alphabet. For example, the stage 'a 'weighs one ton,' b 'weighs two tons, and' z' — 2626 tons.
Build the rocket with the minimal weight or determine, that it is impossible to build a rocket at all. Each stage can be used at most once.
Input
The first line of input contains two integers — nn and kk (1≤k≤n≤501≤k≤n≤50) – the number of available stages and the number of stages to use in the rocket.
The second line contains string ss, which consists of exactly nn lowercase Latin letters. Each letter defines a new stage, which can be used to build the rocket. Each stage can be used at most once.
Output
Print a single integer — the minimal total weight of the rocket or -1, if it is impossible to build the rocket at all.
Examples
input
Copy
5 3 xyabd
output
Copy
29
input
Copy
7 4 problem
output
Copy
34
input
Copy
2 2 ab
output
Copy
-1
input
Copy
12 1 abaabbaaabbb
output
Copy
1
Note
In the first example, the following rockets satisfy the condition:
- "adx" (weight is 1+4+24=291+4+24=29);
- "ady" (weight is 1+4+25=301+4+25=30);
- "bdx" (weight is 2+4+24=302+4+24=30);
- "bdy" (weight is 2+4+25=312+4+25=31).
Rocket "adx" has the minimal weight, so the answer is 2929.
In the second example, target rocket is "belo". Its weight is 2+5+12+15=342+5+12+15=34.
In the third example, n=k=2n=k=2, so the rocket must have both stages: 'a' and 'b'. This rocket doesn't satisfy the condition, because these letters are adjacent in the alphabet. Answer is -1.
题意：给你长度为n的字符串（仅由小写字母构成），是否能从中挑选字母组成一个长度为k的字符串
要求新字符串 从左到右 字典序变大 切相邻两个字典序之差不能<=1 比如 c之后不能是a b c d，
输出新字符串的所有价值之和 a的价值为1,b->2,...z->26
思路：
记录每个字母出现的次数
从a到z扫一遍
#include
#include
#include
#include
#include
#include
#define ll long long
#define INF 0x3f3f3f
using namespace std;
const int N=1000+1000;
char s[N];
int cnt[N];
int main()
{
int n,k,now,c,flag,i;
int ans=0;
scanf("%d%d",&n,&k);
scanf("%s",s);
flag=0;
c=0;
for(i=0;i