攻防世界 reverse新手题 game

game

运行一下，真是个游戏

英文翻译一下
玩游戏
n是灯的序列号，m是灯的状态
如果第n个灯的m为1，则亮，否则熄灭
起初所有的灯都关了
现在你可以输入n来改变它的状态
但是你要注意一件事，如果你改变第N个灯的状态，（N-1）th和（N+1）th的状态也会改变
当所有灯都亮起时，将出现标志
现在，输入n
输入n，n（1-8）
1.△2.○3.◇4.□5.☆6.▽7.（_▽8）／8.（°Д°）0.重启
n=

查看一下无壳，32bit

拉入32位ida查看，找到main函数，F5得到伪代码

void __cdecl main_0()
{
  signed int i; // [esp+DCh] [ebp-20h]
  int v1; // [esp+F4h] [ebp-8h]

  sub_45A7BE(&unk_50B110);
  sub_45A7BE(&unk_50B158);
  sub_45A7BE(&unk_50B1A0);
  sub_45A7BE(&unk_50B1E8);
  sub_45A7BE(&unk_50B230);
  sub_45A7BE(&unk_50B278);
  sub_45A7BE(&unk_50B2C0);
  sub_45A7BE(&unk_50B308);
  sub_45A7BE(&unk_50AFD0);
  sub_45A7BE("|              by 0x61                                 |\n");
  sub_45A7BE("|                                                      |\n");
  sub_45A7BE("|------------------------------------------------------|\n");
  sub_45A7BE(
    "Play a game\n"
    "The n is the serial number of the lamp,and m is the state of the lamp\n"
    "If m of the Nth lamp is 1,it's on ,if not it's off\n"
    "At first all the lights were closed\n");
  sub_45A7BE("Now you can input n to change its state\n");
  sub_45A7BE(
    "But you should pay attention to one thing,if you change the state of the Nth lamp,the state of (N-1)th and (N+1)th w"
    "ill be changed too\n");
  sub_45A7BE("When all lamps are on,flag will appear\n");
  sub_45A7BE("Now,input n \n");
  while ( 1 )
  {
    while ( 1 )
    {
      sub_45A7BE("input n,n(1-8)\n");
      sub_459418();
      sub_45A7BE("n=");
      sub_4596D4("%d", &v1);
      sub_45A7BE("\n");
      if ( v1 >= 0 && v1 <= 8 )
        break;
      sub_45A7BE("sorry,n error,try again\n");
    }
    if ( v1 )
    {
      sub_4576D6(v1 - 1);
    }
    else
    {
      for ( i = 0; i < 8; ++i )
      {
        if ( (unsigned int)i >= 9 )
          j____report_rangecheckfailure();
        byte_532E28[i] = 0;
      }
    }
    j__system("CLS");
    sub_458054();
    if ( byte_532E28[0] == 1
      && byte_532E28[1] == 1
      && byte_532E28[2] == 1
      && byte_532E28[3] == 1
      && byte_532E28[4] == 1
      && byte_532E28[5] == 1
      && byte_532E28[6] == 1
      && byte_532E28[7] == 1 )
    {
      sub_457AB4();
    }
  }
}

看到如下图，可知flag应该在sub_457AB4中，打开

得到

  sub_45A7BE("done!!! the flag is ");
  v59 = 18;
  v60 = 64;
  v61 = 98;
  v62 = 5;
  v63 = 2;
  v64 = 4;
  v65 = 6;
  v66 = 3;
  v67 = 6;
  v68 = 48;
  v69 = 49;
  v70 = 65;
  v71 = 32;
  v72 = 12;
  v73 = 48;
  v74 = 65;
  v75 = 31;
  v76 = 78;
  v77 = 62;
  v78 = 32;
  v79 = 49;
  v80 = 32;
  v81 = 1;
  v82 = 57;
  v83 = 96;
  v84 = 3;
  v85 = 21;
  v86 = 9;
  v87 = 4;
  v88 = 62;
  v89 = 3;
  v90 = 5;
  v91 = 4;
  v92 = 1;
  v93 = 2;
  v94 = 3;
  v95 = 44;
  v96 = 65;
  v97 = 78;
  v98 = 32;
  v99 = 16;
  v100 = 97;
  v101 = 54;
  v102 = 16;
  v103 = 44;
  v104 = 52;
  v105 = 32;
  v106 = 64;
  v107 = 89;
  v108 = 45;
  v109 = 32;
  v110 = 65;
  v111 = 15;
  v112 = 34;
  v113 = 18;
  v114 = 16;
  v115 = 0;
  v2 = 123;
  v3 = 32;
  v4 = 18;
  v5 = 98;
  v6 = 119;
  v7 = 108;
  v8 = 65;
  v9 = 41;
  v10 = 124;
  v11 = 80;
  v12 = 125;
  v13 = 38;
  v14 = 124;
  v15 = 111;
  v16 = 74;
  v17 = 49;
  v18 = 83;
  v19 = 108;
  v20 = 94;
  v21 = 108;
  v22 = 84;
  v23 = 6;
  v24 = 96;
  v25 = 83;
  v26 = 44;
  v27 = 121;
  v28 = 104;
  v29 = 110;
  v30 = 32;
  v31 = 95;
  v32 = 117;
  v33 = 101;
  v34 = 99;
  v35 = 123;
  v36 = 127;
  v37 = 119;
  v38 = 96;
  v39 = 48;
  v40 = 107;
  v41 = 71;
  v42 = 92;
  v43 = 29;
  v44 = 81;
  v45 = 107;
  v46 = 90;
  v47 = 85;
  v48 = 64;
  v49 = 12;
  v50 = 43;
  v51 = 76;
  v52 = 86;
  v53 = 13;
  v54 = 114;
  v55 = 1;
  v56 = 117;
  v57 = 126;
  v58 = 0;
  for ( i = 0; i < 56; ++i )
  {
    *(&v2 + i) ^= *(&v59 + i);
    *(&v2 + i) ^= 0x13u;
  }
  return sub_45A7BE("%s\n");
}

异或，转成Python代码

arr1 = [18, 64, 98, 5, 2, 4, 6, 3, 6, 48, 49, 65, 32, 12, 48, 65, 31, 78, 62, 32, 49, 32,
        1, 57, 96, 3, 21, 9, 4, 62, 3, 5, 4, 1, 2, 3, 44, 65, 78, 32, 16, 97, 54, 16, 44,
        52, 32, 64, 89, 45, 32, 65, 15, 34, 18, 16, 0]
arr2 = [123, 32, 18, 98, 119, 108, 65, 41, 124, 80, 125, 38, 124, 111, 74, 49,
        83, 108, 94, 108, 84, 6, 96, 83, 44, 121, 104, 110, 32, 95, 117, 101, 99,
        123, 127, 119, 96, 48, 107, 71, 92, 29, 81, 107, 90, 85, 64, 12, 43, 76, 86,
        13, 114, 1, 117, 126, 0]
str=''
for i in range(0,56):
    arr2[i] ^= arr1[i]
    arr2[i] ^= 0x13
    str =str + chr(arr2[i]);

print(str)

运行

zsctf{T9is_tOpic_1s_v5ry_int7resting_b6t_others_are_n0t}
找wp，看到有用od做的，还有暴力破解的，还是没太明白。
暴力破解游戏过关的方法，直接123456789，flag出来