java.util.RandomAccessSubList cannot be cast to java.util.ArrayList解决办法

public class subListTest {

	public static void main(String[] args){
		ArrayList list = new ArrayList();		
		list.add(1);
		list.add(2);
		list.add(3);
		list.add(4);
		list.add(5);		
		List listsub = list.subList(0, 3);
		System.out.println(listsub);
	}
}

　　List listsub = list.subList(0, 3); 如果改成下面的式子

     ArrayList listsub = list.subList(0, 3);就会报标题的java.util.RandomAccessSubList cannot be cast to java.util.ArrayList错误。

原因分析是：subList返回的是list，问题就是在subList方法中

public List subList(int fromIndex, int toIndex) {
        return (this instanceof RandomAccess ?
                new RandomAccessSubList(this, fromIndex, toIndex) :
                new SubList(this, fromIndex, toIndex));
    }

　　

 

转载于:https://www.cnblogs.com/yuwenfeng/archive/2013/05/31/3110694.html