python写一个港式梭哈，判断牌型的程序
# -*- coding: utf-8 -*-
"""
Created on Thu Jul 11 15:50:12 2019
@author: leslie lee
"""
"""
经历了几个小时的思考，我发现：
对这个牌值大小进行统计后，五张牌只有下列几种结果
11111 顺子或单牌
1112 一个对
113 三张相同
122 两个对
14 四张相同
23 一个对加三张相同
我通过遍历得到一个统计相同牌值有多少个的字典，然后将字典中的值转成列表，再对列表进行
排序便会得到上面的序列
"""
"""
梭哈时顺子有：
8 9 10 J Q
9 10 J Q K
10 J Q K A
同时我为了简便，将10改成T
"""
def check_straight_flush(hand):
"""检测是不是同花顺"""
if check_flush(hand) and check_straight(hand):
return True
else:
return False
def check_four_of_a_kind(hand):
"""检测是不是四张相同"""
frequencies={}
frequencies_list=[]
ranks = [i[0] for i in hand]
for rank in ranks:
if rank not in frequencies :
frequencies[rank] = 1
else :
frequencies[rank] += 1
for frequency in frequencies.values():
frequencies_list.append(int(frequency))
frequencies_list.sort()
#判断list中是否有值为4
if frequencies_list[1] == 4:
return True
else:
return False
def check_full_house(hand):
""" 检测是不是三张相同加一个对子"""
frequencies={}
frequencies_list=[]
ranks = [i[0] for i in hand]
for rank in ranks:
if rank not in frequencies:
frequencies[rank] = 1
else:
frequencies[rank] += 1
for frequency in frequencies.values():
frequencies_list.append(int(frequency))
frequencies_list.sort()
if frequencies_list[0] == 2:
return True
else:
return False
def check_flush(hand):
"""检测是不是同花"""
frequencies={}
frequencies_list=[]
suits = [i[2] for i in hand]
for suit in suits:
if suit not in frequencies :
frequencies[suit] = 1
else :
frequencies[suit] += 1
for frequency in frequencies.values():
frequencies_list.append(int(frequency))
frequencies_list.sort()
if frequencies_list[0] == 5:
return True
else:
return False
def check_straight(hand):
"""检测是不是顺子"""
frequencies={}
frequencies_list=[]
ranks = [i[0] for i in hand]
for rank in ranks:
if rank not in frequencies:
frequencies[rank] = 1
else:
frequencies[rank] += 1
for frequency in frequencies.values():
frequencies_list.append(int(frequency))
frequencies_list.sort()
#列出顺子的种类，并且对三种顺子及自己拿到的牌用统一的sort方法排序
straight1 = ['8','9','T','J','Q']
straight2 = ['9','T','J','Q','K']
straight3 = ['T','J','Q','K','A']
straight1.sort()
straight2.sort()
straight3.sort()
ranks.sort()
if len(frequencies_list) == 5:
if ranks == straight1 or ranks == straight2 or ranks == straight3 :
return True
else:
return False
else:
return False
def check_three_of_a_kind(hand):
"""检测是不是三张相同"""
frequencies={}
frequencies_list=[]
ranks = [i[0] for i in hand]
for rank in ranks:
if rank not in frequencies:
frequencies[rank] = 1
else:
frequencies[rank] += 1
for frequency in frequencies.values():
frequencies_list.append(int(frequency))
frequencies_list.sort()
if frequencies_list[1] == 1:
if frequencies_list[2] == 3:
return True
else:
return False
else:
return False
def check_two_pairs(hand):
"""检测是不是两个对子"""
frequencies={}
frequencies_list=[]
ranks = [i[0] for i in hand]
for rank in ranks:
if rank not in frequencies:
frequencies[rank] = 1
else:
frequencies[rank] += 1
for frequency in frequencies.values():
frequencies_list.append(int(frequency))
frequencies_list.sort()
if frequencies_list[1] == 2:
return True
else:
return False
def check_one_pairs(hand):
"""检测是不是一个对子"""
frequencies={}
frequencies_list=[]
ranks = [i[0] for i in hand]
for rank in ranks:
if rank not in frequencies:
frequencies[rank] = 1
else:
frequencies[rank] += 1
for frequency in frequencies.values():
frequencies_list.append(int(frequency))
frequencies_list.sort()
if frequencies_list[1] == 1:
if frequencies_list[2] == 1:
if frequencies_list[3] == 2:
return True
else:
return False
else:
return False
else:
return False
def judge(hand):
if check_four_of_a_kind(hand):
return 1
elif check_full_house(hand):
return 2
elif check_flush(hand):
return 3
elif check_straight(hand):
return 4
elif check_three_of_a_kind(hand):
return 5
elif check_two_pairs(hand):
return 6
elif check_one_pairs(hand):
return 7
elif check_straight_flush(hand):
return 8
else:
return 9我想了几个小时，然后参考别人的程序，加上自己的idea，写出了这个可以判断牌型的程序。
港式梭哈，每人手里五张牌，然后判断自己手里的是同花顺，铁支，葫芦，三条，两对，一对，同花，顺子，还是单排。
当然我在编写时，发现把10叫做Ten的是首字母T比较容易编写，所以牌值有：8，9，T，J，Q，K，A
如果谁要使用我的程序，请标明作者leslie lee。