C++ CodeForces-118A. String Task【练习题】

A. String Task
time limit per test2 seconds
memory limit per test256 megabytes
inputstandard input
outputstandard output
Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:

deletes all the vowels,
inserts a character “.” before each consonant,
replaces all uppercase consonants with corresponding lowercase ones.
Vowels are letters “A”, “O”, “Y”, “E”, “U”, “I”, and the rest are consonants. The program’s input is exactly one string, it should return the output as a single string, resulting after the program’s processing the initial string.

Help Petya cope with this easy task.

Input
The first line represents input string of Petya’s program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive.

Output
Print the resulting string. It is guaranteed that this string is not empty.

Examples
input
tour
output
.t.r
input
Codeforces
output
.c.d.f.r.c.s
input
aBAcAba
output
.b.c.b

问题链接：
       http://codeforces.com/problemset/problem/118/A

问题简述：
       输入一串字符，如果英文字母是大写则转换为小写，是元音则去掉，是辅音则在前加“.”,输出处理后的字母。

问题分析：
       先判断字符串种是否为英文字母，然后将大写转换为小写，利用第二个字符串，是元音则跳过，是辅音则先加“.”再加上辅音字母，最后输出处理后的字符串。

遇到问题：
       s1[100],s2[200]会导致提交失败。不初始化s1，s2则会乱码。

贴上代码↓↓↓

#include
#include
#include

using namespace std;

int main()
{
	char s1[150] = { 0 };
	char s2[250] = { 0 };
	char * p1 = s1;
	cin >> p1;
	for (int i = 0, j = 0; i < strlen(p1); i++)
	{
		if (isalpha(*(p1+i)))
			*(p1 + i) = tolower(*(p1 + i));					//大写换小写
		if (*(p1 + i) == 'a' || *(p1 + i) == 'e' || *(p1 + i) == 'i' || *(p1 + i) == 'o' || *(p1 + i) == 'u' || *(p1 + i) == 'y')
			continue;										//如果是元音字母就跳过
		else
		{
			s2[j++] = '.';
			s2[j++] = *(p1 + i);
		}
	}
	cout << s2;
	return 0;
}