leetcode 106. 从中序与后序遍历序列构造二叉树

题目

根据一棵树的中序遍历与后序遍历构造二叉树。

注意:
你可以假设树中没有重复的元素。

例如，给出

中序遍历 inorder = [9,3,15,20,7]
后序遍历 postorder = [9,15,7,20,3]

返回如下的二叉树：

    3
   / \
  9  20
    /  \
   15   7

实现

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* buildTree(vector& inorder, vector& postorder) {
        TreeNode* root = func(inorder, 0, inorder.size() - 1, postorder, 0, postorder.size() - 1);
        return root;
    }
    TreeNode* func(vector& inorder, int instart, int inend, vector& postorder, int poststart, int postend) {
        if (instart > inend || poststart > postend) return NULL;
        TreeNode* root = new TreeNode(postorder[postend]);
        int flag = 0;
        for (int i = instart; i <= inend; i++) {
            if (inorder[i] == postorder[postend]) {
                flag = i;
                break;
            }
        }
        TreeNode* left = func(inorder, instart, flag - 1, postorder, poststart, poststart + flag - instart - 1);
        TreeNode* right = func(inorder, flag + 1, inend, postorder, poststart + flag - instart, postend - 1);
        root->left = left;
        root->right = right;
        return root;
    }
};