luogu1603：斯诺登的密码：字符串与数字的转换

题目连接：该题是luogu试炼场的2-5：T1

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题目大意：
1 给n个单词，里面会有与数字相关的英文；
2 对于这些数字进行一系列的处理，最后输出特定值

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解题思路：
1 主要是掌握字符串的存储
2 字符串与数字的转换

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上代码

//luogu1603：斯诺登的密码
 
//考察字符串的应用 
//1 单词的存储与转化 
//2 排序与输出 

#include
#include
#include
using namespace std;
char s[10][20];
int ls=0,l,la=0,a[10];
char s1[30][20]={"0",
	"one","two","three","four","five","six","seven",
	"eight","nine","ten","eleven","twelve","thirteen","fourteen",
	"fifteen","sixteen","seventeen","eighteen","nineteen","twenty"
};
char s2[10][20]={ "0","a","both","another"};
char s3[10][20]={ "0","first","second","third"};
int main()
{
	while(scanf("%s",s[++ls])!=EOF) //读入的细节处理 
	{
		l=strlen(s[ls]);
		for(int i=0;i='A'&&s[ls][i]<='Z') //过滤大写 
				s[ls][i]=s[ls][i]-'A'+'a';
		}	
	}
	
	for(int i=1;i<=ls;i++)//查出所有的数字 
	{
		for(int j=1;j<=20;j++)//标准数字 
		{
			if(strcmp(s[i],s1[j])==0) a[++la]=j;
		}
		for(int j=1;j<=3;j++)//非标数字 1 
		{
			if(strcmp(s[i],s2[j])==0) a[++la]=j;
		}
		for(int j=1;j<=3;j++)//非标数字 2
		{
			if(strcmp(s[i],s3[j])==0) a[++la]=j;
		}
	}
	
	for(int i=1;i<=la;i++)//字符转数字 
	{
		a[i]*=a[i];
		a[i]%=100;
	}
	
	sort(a+1,a+1+la);//排序求最小值 
	
	printf("%d",a[1]);
	
	for(int i=2;i<=la;i++)
	{
		printf("%02d",a[i]);
	}
	return 0;
}