HDU--1228--A+B问题

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output

对每个测试用例输出1行,即A+B的值.

Sample Input
one + two =
three four + five six =
zero seven + eight nine =
zero + zero =
Sample Output
3
90
96

思路：1.构造一个dex数组用于直接查询对应的数字；

2.对于输入格式需要注意：xx xx + xx xx = 以及xx xx + xx = 都容易出错，需要提前判断"+"和"="出现的位置；

#include
#include
#include
#include
#include
using namespace std;
const int maxa=1e2+10;
char z[maxa],zz[maxa],y[maxa],yy[maxa];
char ja[maxa],den[maxa];
char dex[12][maxa]={"zero","one","two","three","four","five","six","seven","eight","nine","ten"};//len=12
int znum,ynum;
int function(char *a){
	for(int i=0;i<12;i++)
		if(!strcmp(a,dex[i]))	
			return i;
}
int main(){
	while(true){
		cin>>z;
		cin>>ja;
		if(!strcmp(ja,"+"))	znum=function(z);
		else{ 	
			cin>>zz;	
			znum=10*function(z)+function(ja);
		} 
		cin>>y;
		cin>>den;
		if(!strcmp(den,"="))	 ynum=function(y);
		else{
			cin>>yy;
			ynum=10*function(y)+function(den);
		} 
		if(!strcmp(z,dex[0])&&!strcmp(y,dex[0]))	break;
		cout<