根据用户经纬度，sql计算距离并排序

java 计算

public class DistanceUtil {

	// 地球平均半径
	private static final double EARTH_RADIUS = 6378137;

	// 把经纬度转为度（°）
	private static double rad(double d) {
		return d * Math.PI / 180.0;
	}

	/**
	 * 根据两点间经纬度坐标（double值），计算两点间距离，单位：千米
	 * @author ershuai
	 * @param lng1
	 * @param lat1
	 * @param lng2
	 * @param lat2
	 * @return
	 */
	public static double getDistance(double lng1, double lat1, double lng2, double lat2) {
		double radLat1 = rad(lat1);
		double radLat2 = rad(lat2);
		double a = radLat1 - radLat2;
		double b = rad(lng1) - rad(lng2);
		double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a / 2), 2) + Math.cos(radLat1) * Math.cos(radLat2) * Math.pow(Math.sin(b / 2), 2)));
		s = s * EARTH_RADIUS;
		s = s / 1000;
		DecimalFormat df = new DecimalFormat("#.00");
		s = Double.parseDouble(df.format(s));
		return s;
	}
	
	public static void main(String[] args) {
		double distance1 = getDistance(104.046115, 30.6030110000, 104.074666, 30.611842);
		System.out.println("Distance is: " + distance1 + " km");
	}
}

sql 计算

SELECT
	es_name,
	es_lon,
	es_lat,
	ROUND(
		6378.138 * 2 * ASIN(
			SQRT(
				POW(
					SIN(
						(
							30.611842 * PI() / 180 - es_lat * PI() / 180
						) / 2
					),
					2
				) + COS(30.611842 * PI() / 180) * COS(es_lat * PI() / 180) * POW(
					SIN(
						(
							104.074666 * PI() / 180 - es_lon * PI() / 180
						) / 2
					),
					2
				)
			)
		) * 1000
	) AS distance_um
FROM
	c_ershuai
ORDER BY
	distance_um ASC