UVa-循环小数

Uva-202循环小数：

#include 
#include 
#include 
#include 
using namespace std;
int r[3003],u[3003],s[3003];
int main()
{
    int n,m,t;
    while (~scanf("%d%d",&n,&m)) {
        t = n;
        memset(r, 0, sizeof(r));
        memset(u, 0, sizeof(u));
        int count = 0;
        r[count ++] = n/m;
        n = n%m;
        while (!u[n] && n) {
            u[n] = count;
            s[count] = n;
            r[count ++] = 10*n/m;
            n = 10*n%m;
        }
        printf("%d/%d = %d",t,m,r[0]);
        printf(".");
        for (int i = 1 ; i < count && i <= 50 ; ++ i) {
            if (n && s[i] == n) printf("(");
            printf("%d",r[i]);
        }
        if (!n) printf("(0");
        if (count > 50) printf("...");
        printf(")\n");
        printf("   %d = number of digits in repeating cycle\n\n",!n?1:count-u[n]);
    }
    return 0;
}