LeetCode:237

题目:Delete Node in a Linked List(从列表中删除指定结点)
描述:Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
例子:Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

解法:(参考博客:http://www.cnblogs.com/tjuloading/p/4648652.html)
将当前结点伪装成下一个结点,然后删除下一个结点即可。(真是太巧妙了,以前都没想到过这种删除方法)

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public void deleteNode(ListNode node) {
        node.val = node.next.val;
        node.next = node.next.next;
    }
}

转载于:https://www.cnblogs.com/wenbaoli/p/5655740.html

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