【Ｃ语言】建立动态链表并输出链表

写一个函数建立一个有3名学生数据的单向动态链表

//建立静态链表
#include
#include
#include
#include
#define LEN sizeof(struct Student)

struct Student
{
    long num;
    float score;
    struct Student*next;

};

int n;

struct Student*creat()  //建立链表的函数
{
    struct Student*head;
    struct Student *p1, *p2;
    n = 0;
    p1 = p2 = (struct Student*)malloc(LEN);
    scanf_s("%ld,%f", &p1->num, &p1->score);
    head = NULL;
    while (p1->num != 0)
    {
        n = n + 1;
        if (n == 1)
        {
            head = p1;
        }
        else
        {
            p2->next = p1;
        }
        p2 = p1;
        p1 = (struct Student*)malloc(LEN);
        scanf_s("%ld,%f", &p1->num, &p1->score);

    }
    p2->next = NULL;
    return(head);

}

void print(struct Student *head)   //输出链表函数
{
    struct Student* p;
    printf("\nNow,These %d records are:\n", n);
    p = head;
    if (head != NULL)
    {
        do
        {
            printf("%ld %5.1f\n", p->num, p->score);
            p = p->next;

        } while (p != NULL);

    }

}
int main()
{
    struct Student*head;
    head = creat();//调用creat函数，返回第一个节点的起始地址
    print(head);   //调用print函数
    system("pause");
    return 0;
}