Leetcode刷题记——11. Container With Most Water（装最多水的容器）

一、题目叙述：

Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

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二、解题思路：

这个我真的没想出来，头脑简单的用暴力写，显然复杂度到n2了，就超时了，最后也没想出来怎么弄。所以看了别人的做法，结果非常简单，复杂度也就O(N)。基本思路是这样的：在数组前后各放一个指针，计算此时容器的能盛水的量，因为显然此时的矩形长达到了最长，接着将短的一边的指针向前移，向前移时，矩形长已经在缩短了，只要想办法提升宽面积才能增大，由此。。。

三、源源源码：

public class Solution 
{
    public int maxArea(int[] height) 
    {
     int min = 0;
     int max = height.length - 1;
     int maxarea = 0;
     int temp = 0;
     while (min < max)
     {
    	 temp = (max - min) * Math.min(height[min], height[max]);
    	 if (temp > maxarea) maxarea = temp;
    	 if (height[min] < height[max]) min ++;
    	 else max --;
     }
     return maxarea;
    }
    public static void main(String args[])
    {
    	int[] a = {1,1};
    	Solution solution = new Solution();
    	System.out.println(solution.maxArea(a));
    	
    }
}