# -*- coding: utf-8 -*-
# 在排序时, 可以用lambda表达式将对象map成keys
# 亦可以使用operator包中的attrgetter和itemgetter函数以提高效率
# 参考 http://wiki.python.org/moin/HowTo/Sorting
# 考虑 Student 对象
class Student:
def __init__(self, name, grade, age):
self.name = name
self.grade = grade
self.age = age
def __repr__(self):
return repr((self.name, self.grade, self.age))
# 建立一组Student对象
students = [
Student('jane', 'B', 12),
Student('john', 'A', 12),
Student('dave', 'B', 10),
]
from operator import itemgetter, attrgetter
# 对students按照年龄排序
print sorted(students, key=attrgetter('age'))
# 其等价于
print sorted(students, key=lambda o: o.age)
# 输出: >>> [('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]
# 亦可以按多个key排序, 先按age再按grade排序
print sorted(students, key=attrgetter('age', 'grade'))
# 输出: >>> [('dave', 'B', 10), ('john', 'A', 12), ('jane', 'B', 12)]