3-1-2 多分支结构(Chained)有
一元二次方程
希望程序自动多次计算,然后输入‘q’退出循环
注:下一篇正式讲这个
while 循环继续条件:
缩进语句块(循环体)【体内要设定条件改变语句】
其余语句
1.只是将if改成while
count = 0
while count < 5:
print 'programming is fun!'
count += 1
count = 0
while count < 5:
print 'hello world!'
count += 1
无法输入大写英文字母,只能黏贴,why
1+2+3+...+10
i = 1
s = 0
while i <= 10:
s += i
i += 1
print s
输出55
依旧输出55
因为0+1+...+10
count = 0
while count < 10:
print count
留意:
用control+c断掉循环
count = 0
while count < 10:
print count
count -= 1
count = 0
while count < 10:
print count
count += 1
count = 0
while count < 10:
if count % 2 == 0:
print count
count = 0
while count < 10:
if count % 2 == 0:
print count
count += 1
count = 0
while count < 10:
if count % 2 == 0:
print count
count += 1
0
2
4
6
8
测验1-2求100以内所有偶数之和的程序
sum = 0
i = 0
while i < 100:
if i % 2 == 0:
sum += i
i += 2
print sum
2+2+2+...+2
循环可以一直继续