Codeforces Round #634 (Div. 3)

problem: (B) Construct the String

You are given three positive integers n, a and b. You have to construct a string s of length n consisting of lowercase Latin letters such that each substring of length a has exactly b distinct letters. It is guaranteed that the answer exists.

You have to answer t independent test cases.

Recall that the substring s[l…r] is the string sl,sl+1,…,sr and its length is r−l+1. In this problem you are only interested in substrings of length a.

Input
The first line of the input contains one integer t (1≤t≤2000) — the number of test cases. Then t test cases follow.

The only line of a test case contains three space-separated integers n, a and b (1≤a≤n≤2000,1≤b≤min(26,a)), where n is the length of the required string, a is the length of a substring and b is the required number of distinct letters in each substring of length a.

It is guaranteed that the sum of n over all test cases does not exceed 2000 (∑n≤2000).

Output
For each test case, print the answer — such a string s of length n consisting of lowercase Latin letters that each substring of length a has exactly b distinct letters. If there are multiple valid answers, print any of them. It is guaranteed that the answer exists.

Example
input
4
7 5 3
6 1 1
6 6 1
5 2 2
output
tleelte
qwerty
vvvvvv
abcde

b没有用处,直接循环,主要看思路

代码:

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;
/*int max(int x,int y)
{
    return x>y?x:y;
}*/
int main()
{
    char str[2005];
    int t,n,a,b;
    scanf("%d",&t);
    while(t--){
        scanf("%d%d%d",&n,&a,&b);
        for(int i=0;i<n;i++){
            str[i]='a'+i%b;
        }
        str[n]='\0';
        printf("%s\n",str);
    }
    return 0;
}

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