第五届新疆省ACM-ICPC程序设计竞赛（重现赛）部分题解

B：判断奇数堆的数量为奇数输出n否则0

#include
using namespace std;
#define clr(a,b) memset(a,b,sizeof(a))
const int maxn=100000+5;
int n,s[maxn];
int main()
{
    cin>>n;
    int ever=0,odd=0;
    for(int i=1;i<=n;++i)
    {
        cin>>s[i];
        if(s[i]%2){odd++;}
        else      {ever++;}
    }
    if(odd%2){cout<

---

D：排序按每次可减少的钱最少优秀

#include
using namespace std;
#define clr(a,b) memset(a,b,sizeof(a))
const int maxn=100000+5;
int n;
struct Node
{
    int a;
    double p;
    bool operator < (const Node &b)const{
        return a*(1-b.p)>n;
    for(int i=1;i<=n;++i){cin>>node[i].a>>node[i].p;}
    sort(node+1,node+1+n);
    double ans=0;
    double p=1;
    for(int i=1;i<=n;++i)
    {
        ans+=node[i].a*p;
        p*=node[i].p;
    }
    printf("%.6f\n",ans);
    return 0;
}

---

F：二分搜索下搜索第一个小于L，上搜索第一个大于R

#include
#include
#include
#include
#include
#include
#include
#include
using namespace std;
#define clr(a,b) memset(a,b,sizeof(a))
const int maxn = 100000 + 5;
struct Circle {
	int l, r;
}cir1[maxn], cir2[maxn];
int n;
int cmp1(Circle a, Circle b)
{
	if (a.l == b.l) { return a.r < b.r; }
	return a.l < b.l;
}
int cmp2(Circle a, Circle b)
{
	if (a.r == b.r) { return a.l < b.l; }
	return a.r < b.r;
}
int find1(double tm)
{
	int l = 1, r = n;
	while (l <= r)
	{
		int mid = (l + r) / 2;
		if (cir2[mid].r >= tm) { r = mid - 1; }
		else { l = mid + 1; }
	}
	while (r > 0 && cir2[r].r >= tm) { r--; }
	return r;
}
int find2(double tm)
{
	int l = 1, r = n;
	while (l <= r)
	{
		int mid = (l + r) / 2;
		if (cir1[mid].l <= tm) { l = mid + 1; }
		else { r = mid - 1 ; }
	}
	while (cir1[l].l <= tm&&l<=n) { l++; }
	return n - l+1;
}
int main()
{
	cin >> n;
	double p, r;
	for (int i = 1; i <= n; ++i)
	{
		cin >> p >> r;
		cir1[i].l = cir2[i].l = p - r;
		cir1[i].r = cir2[i].r = p + r;
	}
	sort(cir1+1, cir1 + n+1, cmp1);
	sort(cir2+1, cir2 + n+1, cmp2);
	int sum = 0;
	for (int i = 1; i <= n; ++i)
	{
		sum += find2(cir1[i].r);
	}
	cout << sum<< endl;
	return 0;
}

---

G：纯模板严格单调递增子序列

#include
using namespace std;
#define clr(a,b) memset(a,b,sizeof(a))
const int maxn=50000+5;
int n,s[maxn],dp[maxn];
void LCS()
{
    int len=0;
    dp[0]=s[1];
    for(int i=1;i<=n;++i)
    {
        if(s[i]>dp[len]){dp[len+1]=s[i];len++;}
        else
        {
            int t=lower_bound(dp,dp+len,s[i])-dp;
            dp[t]=s[i];
        }
    }
    cout<>n;
    for(int i=1;i<=n;++i)
    {
        cin>>s[i];
    }
    LCS();
    return 0;
}

---

I：排序暴力直接跑

#include
using namespace std;
#define clr(a,b) memset(a,b,sizeof(a))
const int maxn=100000+5;
struct Node{
    int a;
    int b;
}node[maxn];
int n,a1;
int cmp(Node a,Node b)
{
    if(a.a==b.a){return a.b>b.b;}
    return a.a>b.a;
}
int main()
{
    cin>>n>>a1;
    for(int i=1;i>node[i].a;}
    for(int i=1;i>node[i].b;}
    int ans=a1;
    int flag=1;
    while(flag)
    {
        flag=0;
        for(int i=1;inode[i].a){continue;}
            flag=1;
            while(ans>=0&&node[i].a>=ans)
            {
                ans--;
                node[i].a-=node[i].b;
            }
            if(ans<0){break;}
        }
        if(ans<0){break;}
    }
    if(ans>=0){cout<