Linux C中读取/dev/input/event设备来判断键盘按键是否按下

code:

#include 
#include 
#include 
#include 
#include 
#include 

#define DEV_PATH "/dev/input/event2"   //difference is possible

int main()
{
	int keys_fd;
	char ret[2];
	struct input_event t;
	keys_fd=open(DEV_PATH, O_RDONLY);
	if(keys_fd <= 0)
	{
		printf("open /dev/input/event2 device error!\n");
		return -1;
	}
	while(1)
	{
		if(read(keys_fd, &t, sizeof(t)) == sizeof(t))
		{
			if(t.type==EV_KEY)
				if(t.value==0 || t.value==1)
				{
					printf("key %d %s\n", t.code, (t.value) ? "Pressed" : "Released");
					if(t.code == KEY_ESC)
						break;
				}
		}
	}
	close(keys_fd);
	return 0;
}

运行效果截图:


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