两个线程交替打印1-100

public class Solution2 {
    private static final Object lock = new Object();  //表示对象锁

    private volatile int index = 1;           //表示要输出的数字

    private volatile boolean aHasPrint = false;      //记录A是否被打印过

    class A implements Runnable {
        @Override
        public void run() {
            for (int i = 0; i < 50; i++) {
                synchronized (lock) {
                    while (aHasPrint) {              //如果A已经打印过就进行阻塞
                        try {
                            lock.wait();
                        } catch (InterruptedException e) {
                            e.printStackTrace();
                        }
                    }
                    System.out.println("A:" + index);    //A没有打印过则输出A的值
                    index++;                   //输出的值增加1
                    aHasPrint = true;             //表示A已经打印过
                    lock.notifyAll();            //唤醒其它线程执行
                }
            }
        }
    }

    class B implements Runnable {
        @Override
        public void run() {
            for (int i = 0; i < 50; i++) {
                synchronized (lock) {
                    while (!aHasPrint) {               //如果A没有打印过则阻塞
                        try {
                            lock.wait();
                        } catch (InterruptedException e) {
                            e.printStackTrace();
                        }
                    }
                    System.out.println("B:" + index);  //输出B的值
                    index++;                 //计数加一
                    aHasPrint = false;          //B打印完了说明新的一轮开始了,将标识为计为A没有打印过
                    lock.notifyAll();          //唤醒阻塞线程
                }
            }
        }
    }


    public static void main(String[] args) {
        Solution2 solution2 = new Solution2();
        Thread threadA = new Thread(solution2.new A());
        Thread threadB = new Thread(solution2.new B());
        threadA.start();
        threadB.start();
    }
}

 相关代码 https://github.com/LiWangCai/blogRelated 可自行获取

转载于:https://www.cnblogs.com/liwangcai/p/10741644.html

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