oracle根据状态统计近7天的数据

---查询7天的数据

select 
  a.today as "day",
    nvl(b.general,0) as "general",
    nvl(b.larger,0) as "larger",
    nvl(b.great,0) as "great",
    nvl(b.most,0) as "most"
FROM 
(SELECT 
    to_char (SYSDATE- LEVEL + 1, 'yyyy-mm-dd') today
  FROM
    DUAL connect BY LEVEL <= 7) a
LEFT JOIN 
    (    select to_char(t.CREATE_TIME_,'YYYY-MM-dd') as day,
    SUM(CASE t.LEVEL_ WHEN '1' THEN 1 ELSE 0 END) AS general,
    SUM(CASE t.LEVEL_ WHEN '2' THEN 1 ELSE 0 END) AS larger,
    SUM(CASE t.LEVEL_ WHEN '3' THEN 1 ELSE 0 END) AS great,
    SUM(CASE t.LEVEL_ WHEN '4' THEN 1 ELSE 0 END) AS most
     from QUALITY_PROBLEM t 
    WHERE  t.project_id_ = '119993794937487360' 
  GROUP BY to_char(t.CREATE_TIME_,'YYYY-MM-dd')) b on a.today=b.day order by a.today