java将xml解析,然后将其转换为json格式(②)

上一篇文章只是一个model!!

但是如果是两个model呢!因为我写的项目中就是需要用两个model获取!我先把我项目中从后台接收的xml列出来!


 
   true
   
    
     
      0
       Normal
       正常
     
     
       0
       Normal
       暂停
     
   
 

要想解析这样的model需要用另外一种格式:

import java.util.ArrayList;
import java.util.List;
import net.sf.json.JSONArray;
import net.sf.json.JSONObject;

/**
 * 将model存在list集合中,并将集合转换为json格式
 * */
public class xmlJdom {
	public static void main(String[] args) {
		Student s1=new Student();
		s1.setAge(123);
		s1.setNameString("name");
		Student s2=new Student();
		s2.setAge(1234);
		s2.setNameString("what");
		Teacher teacher=new Teacher();
		teacher.setsAge(11);
		teacher.setsName("teacher");
		List lists=new ArrayList();
		lists.add(s1);
		lists.add(s2);
		teacher.setStudent(lists);
		new JSONObject();
		JSONObject jsonObject = JSONObject.fromObject(teacher); 
		System.out.println(jsonObject); 
		List list = new ArrayList();    
		list.add(s1); 
		list.add(s2);
		JSONArray jsonArr= JSONArray.fromObject(list); 
		System.out.println(jsonArr);
	}
}

输出的内容为:

{"sAge":11,"sName":"teacher","student":[{"age":123,"nameString":"name"},{"age":1234,"nameString":"what"}]}
[{"age":123,"nameString":"name"},{"age":1234,"nameString":"what"}]


两个model:Student和Teacher

teacher里面包含student的list集合:

public class Student {  
  
    private String nameString;  
    private int age;  
    
    public String getNameString() {  
        return nameString;  
    }  
    public void setNameString(String nameString) {  
        this.nameString = nameString;  
    }  
    public int getAge() {  
        return age;  
    }  
    public void setAge(int age) {  
        this.age = age;  
    }  
      
}  

import java.util.List;


public class Teacher {
	private String sName;
	private int sAge;
	private List student;
	public List getStudent() {
		return student;
	}
	public void setStudent(List student) {
		this.student = student;
	}
	public String getsName() {
		return sName;
	}
	public void setsName(String sName) {
		this.sName = sName;
	}
	public int getsAge() {
		return sAge;
	}
	public void setsAge(int sAge) {
		this.sAge = sAge;
	}
}

这样就ok!现在已经学会了举一反三了!

如需转载请注明出处:Finder_畅畅




你可能感兴趣的:(java,json,arraylist,object,instance,class)