浙江大学PAT_甲级_1028. List Sorting (25)

题目链接：点击打开链接

Excel can sort records according to any column. Now you are supposed to imitate this function.

Input

Each input file contains one test case. For each case, the first line contains two integers N (<=100000) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output

For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.

Sample Input 1

3 1
000007 James 85
000010 Amy 90
000001 Zoe 60

Sample Output 1

000001 Zoe 60
000007 James 85
000010 Amy 90

Sample Input 2

4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98

Sample Output 2

000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60

Sample Input 3

4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90

Sample Output 3

000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90

我的c++代码：

#include
#include  
#include  
#include
using namespace std;
struct student
{
	int id; //为节省时间，id用Int类型，不用String
	char name[9];//姓名用char,
	int grade;//分数
};
int c = 1;//控制比较方法
bool compare(student a, student b)//比较方法
{
	if (c == 1)//比较id
	{
		return(a.id < b.id);
	}
	else if (c == 2)//比较名字
	{
		if (strcmp(a.name, b.name) == 0)//名字相同，同一个人，比较id
			return a.id < b.id;
		else
			return strcmp(a.name, b.name) < 0;
	}
	else//比较分数
	{
		if (a.grade == b.grade)//分数相同，比较id
			return a.id < b.id;
		else
			return(a.grade < b.grade);
	}
}
int main()
{
	int n = 0,i=0;//n学生人数
	scanf("%d %d", &n, &c);
	vectorstu_vec(n);//要分配vecto的size
	for (i = 0; i < n; i++)
	{
		cin >> stu_vec[i].id>> stu_vec[i].name >> stu_vec[i].grade;
	}
	sort(stu_vec.begin(),stu_vec.end(),compare);
	for (auto j : stu_vec)//遍历vec
	{
		printf("%0.6d %s %d\n", j.id,j.name,j.grade);//%0.6d把id补足为6个长度
	}
	//system("pause");
	return 0;
}