mysql把一个字段按指定字符拆分并按字母和数字排序

大概的需求是想把下面的warehouse字段拆分开，然后先按字母排序，再按第二个数字排序，在按第三个数字排序，以下代码仅作为参考。

MySQL：

SELECT id,warehouse, 
#LENGTH( warehouse) - LENGTH(REPLACE( warehouse,'-','' )) AS 减号个数,
SUBSTRING_INDEX(warehouse,'-',1) AS 尺寸,
(
    CASE 
    WHEN LENGTH( warehouse) - LENGTH(REPLACE( warehouse,'-','' ))=1 THEN substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1)+0
    WHEN LENGTH( warehouse) - LENGTH(REPLACE( warehouse,'-','' ))=2 THEN SUBSTRING_INDEX(substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1),'-',1)+0
    END
)
AS 楼层,
#LOCATE('-',substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1)) AS 第二个减号位置,
(
    CASE 
    WHEN LENGTH( warehouse) - LENGTH(REPLACE( warehouse,'-','' ))=1 THEN 0
    WHEN LENGTH( warehouse) - LENGTH(REPLACE( warehouse,'-','' ))=2 THEN substring(substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1),LOCATE('-',substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1))+1,length(substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1))-1)+0
    END
)
AS 房号
FROM warehouse 
ORDER BY 尺寸,楼层,房号

上面是mysql的，如果是sqlserver，需要简单的修改几个函数。

sqlserver：

SELECT id,warehouse, 
LEFT (warehouse, charindex('-', warehouse) - 1) AS 尺寸,
(
    CASE 
    WHEN LEN( warehouse) - LEN(REPLACE( warehouse,'-','' ))=1 THEN substring(warehouse,charindex('-',warehouse)+1,LEN(warehouse)-1)+0
    WHEN LEN( warehouse) - LEN(REPLACE( warehouse,'-','' ))=2 THEN LEFT(stuff(warehouse,1,charindex('-',warehouse),''),charindex('-',stuff(warehouse,1,charindex('-',warehouse),''))-1)+0
    END
)
AS 楼层,
(
    CASE 
    WHEN LEN( warehouse) - LEN(REPLACE( warehouse,'-','' ))=1 THEN 0
    WHEN LEN( warehouse) - LEN(REPLACE( warehouse,'-','' ))=2 THEN substring(substring(warehouse,charindex('-',warehouse)+1,LEN(warehouse)-1),charindex('-',substring(warehouse,charindex('-',warehouse)+1,LEN(warehouse)-1))+1,LEN(substring(warehouse,charindex('-',warehouse)+1,LEN(warehouse)-1))-1)+0
    END
)
AS 房号
FROM warehouse 
ORDER BY 尺寸,楼层,房号

排序后的结果为

如果拆分出来的第二个字符串(也就是‘楼层’字段)中存在字母，可以再做修改，这里用正则，也可以用LIKE关键字做判断。

MySQL：

SELECT id,warehouse, 
#LENGTH( warehouse) - LENGTH(REPLACE( warehouse,'-','' )) AS 减号个数,
SUBSTRING_INDEX(warehouse,'-',1) AS 尺寸,
(
    CASE 
    WHEN LENGTH( warehouse) - LENGTH(REPLACE( warehouse,'-','' ))=1
    THEN(
     	CASE
     	WHEN substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1) REGEXP '[a-z]'=0
     	THEN substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1)+0
     	WHEN substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1) REGEXP '[a-z]'=1
     	THEN substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1)
     	END
     	)
    WHEN LENGTH( warehouse) - LENGTH(REPLACE( warehouse,'-','' ))=2 
    THEN(
     	CASE
     	WHEN SUBSTRING_INDEX(substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1),'-',1) REGEXP '[a-z]'=0
     	THEN SUBSTRING_INDEX(substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1),'-',1)+0
     	WHEN SUBSTRING_INDEX(substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1),'-',1) REGEXP '[a-z]'=1
     	THEN SUBSTRING_INDEX(substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1),'-',1)
     	END
     	)
    END
)
AS 楼层,
#LOCATE('-',substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1)) AS 第二个减号位置,
(
    CASE 
    WHEN LENGTH( warehouse) - LENGTH(REPLACE( warehouse,'-','' ))=1 THEN 0
    WHEN LENGTH( warehouse) - LENGTH(REPLACE( warehouse,'-','' ))=2 THEN substring(substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1),LOCATE('-',substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1))+1,length(substring(warehouse,LOCATE('-',warehouse)+1,length(warehouse)-1))-1)+0
    END
)
AS 房号
FROM warehouse 
ORDER BY 尺寸,楼层,房号

排序后的结果