Python实现登录vcloud并访问其资源

上周需要用python访问vcloud上的资源，但是vcloud有个登录认证过程，需要将头信息加入到请求中，经过几番搜寻，终于找到解决方案。

参考地址：http://stackoverflow.com/questions/11395224/vcloud-director-org-user-authentication-for-restapi-in-python

我用用RESTClient的访问过程是：
1）先用POST:https://your_ip/api/sessions（附加头信息有authorization(username:password),headers("Accept":"application/*+xml;version=5.1")）登录vcloud。
2）然后再通过REST API 访问vcloud上的资源（带有上述头信息），eg:GET https://your_ip/api/org/。

Python实现代码：

'''
Created on 2013-11-5

@author: sj_mei
'''
import urllib2
import base64
import cookielib
from lib.utils import MiscUtils

class VcloudRest:
    def __init__(self,url,username,password):
        
        MiscUtils.assert_true(url is not None,"No url defined")
        MiscUtils.assert_true(username is not None,"No user name defined")
        MiscUtils.assert_true(password is not None,"No password defined")
        
        self._url = url
        self._username = username
        self._password = password
        self._autheader = self.encodeAuth(username, password)
        self.login(url, username, password)
        
    def login(self,url,username,password,method='POST'):
        cookiehandler = urllib2.HTTPCookieProcessor(cookielib.CookieJar())
        httpshandler = urllib2.HTTPSHandler()
        opener = urllib2.build_opener(cookiehandler,httpshandler)
        urllib2.install_opener(opener)
        request = urllib2.Request(url)
        
        request.add_header("Authorization", self._autheader)
        request.add_header("Accept",'application/*+xml;version=5.1')
        
        request.get_method = lambda: method
        try:
            connection = opener.open(request)
        except urllib2.HTTPError,e:
            connection = e
        
        if connection.code == 200:
            data = connection.read()
            print "Data :", data
        else:
            print "ERRROR", connection.code
        
    def encodeAuth(self,username,password):
        base64string = base64.encodestring('%s:%s' % (username, password))[:-1]
        authheader =  "Basic %s" % base64string
        return authheader
    
    def get_header(self):
        headers = {'Accept':'application/*+xml;version=5.1','Authorization':self._autheader}
        return headers
    
    def get(self,url):
        headers = self.get_header()
        req = urllib2.Request(url,None,headers)
        req.get_method = lambda: 'GET'
        try:
            response = urllib2.urlopen(req)
            content = response.read()
            print "Content: ",content
        except urllib2.HTTPError,e:
            print "ERROR: ",e


if __name__ == '__main__':
    vRest = VcloudRest("https://your_ip/api/sessions","username@your_vcloud","password")
    
    resource = "https://your_ip/api/org"
    vRest.get(resource)

附vCloud REST API链接： http://pubs.vmware.com/vcd-51/index.jsp#doc/index.html