最长连续递增子序列的长度

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Longest Continuous Increasing Subsequence

问题:

Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.

Example 2:

Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1.

Note: Length of the array will not exceed 10,000.

解决:

① 求最长连续递增子序列。暴力解决。

class Solution { //6ms
    public int findLengthOfLCIS(int[] nums) {
        int res = 0;
        int count = 0;
        for (int i = 0;i < nums.length;i ++){
            if (i == 0 || nums[i - 1] < nums[i]){
                res = Math.max(res,++ count);
            }else {
                count = 1;
            }
        }
        return res;
    }
}

 

转载于:https://my.oschina.net/liyurong/blog/1606801

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