先存一下,稍后写注释
#include
using namespace std;
#define pb emplace_back
#define mp make_pair
#define eps 1e-8
typedef long long ll;
const int maxn = 1e5+ 7;
const ll mod = 1e9 + 7;
struct P{
ll m[2][2];
P(){
memset(m, 0, sizeof(m));}
}A, B;
char s[maxn];
P mul(P a, P b)
{
P ans = P();
for(int i = 0; i < 2; i ++)
{
for(int j = 0; j < 2; j ++)
{
for(int k = 0; k < 2; k ++)
{
ans.m[i][j] += (a.m[i][k] * b.m[k][j]) % mod;
ans.m[i][j] %= mod;
}
}
}
return ans;
}
P tree[maxn << 2][2];
int lazy[maxn << 2];
ll lc(ll p)
{
return p << 1;
}
ll rc(ll p)
{
return p << 1 | 1;
}
void pushup(ll p)
{
tree[p][0] = mul(tree[lc(p)][0], tree[rc(p)][0]);
tree[p][1] = mul(tree[lc(p)][1], tree[rc(p)][1]);
}
void build(ll p, ll l, ll r)
{
lazy[p] = 0;
if(l == r)
{
if(s[r] == 'A')
tree[p][0] = A, tree[p][1] = B;
else
tree[p][0] = B, tree[p][1] = A;
return ;
}
ll mid = l + r >> 1;
build(lc(p), l, mid);
build(rc(p), mid + 1, r);
pushup(p);
}
void pushdown(ll p)
{
if(lazy[p])
{
lazy[lc(p)] ^= 1;
lazy[rc(p)] ^= 1;
swap(tree[lc(p)][0], tree[lc(p)][1]);
swap(tree[rc(p)][0], tree[rc(p)][1]);
lazy[p] = 0;
}
}
void update(ll p, ll nl, ll nr, ll l, ll r)
{
if(nl <= l && r <= nr)
{
swap(tree[p][0], tree[p][1]);
lazy[p] ^= 1;
return ;
}
pushdown(p);
ll mid = l + r >> 1;
if(nl <= mid)
update(lc(p), nl, nr, l, mid);
if(nr > mid)
update(rc(p), nl, nr, mid + 1, r);
pushup(p);
}
void query(ll p, ll nl, ll nr, ll l, ll r, P &ans)
{
if(nl <= l && r <= nr)
{
ans = mul(ans, tree[p][0]);
return ;
}
ll mid = l + r >> 1;
pushdown(p);
if(nl <= mid)
query(lc(p), nl, nr, l, mid, ans);
if(nr > mid)
query(rc(p), nl, nr, mid + 1, r, ans);
pushup(p);
}
int n, m, a, b, l, r, op;
int main()
{
scanf("%d%d", &n, &m);
scanf("%s", s + 1);
A.m[0][0] = A.m[1][0] = A.m[1][1] = B.m[0][0] = B.m[0][1] = B.m[1][1] = 1;
build(1, 1, n);
for(int i = 0; i < m; i ++)
{
scanf("%d", &op);
if(op == 1)
{
scanf("%d%d", &l ,&r);
update(1, l, r, 1, n);
}
else
{
scanf("%d%d%d%d", &l, &r, &a, &b);
P base = P();
base.m[0][0] = base.m[1][1] = 1;
query(1, l, r, 1, n, base);
P ans = P();
ans.m[0][0] = a;
ans.m[0][1] = b;
ans = mul(ans, base);
//printf("%lld %lld\n", res.m[0][0], res.m[1][1]);
printf("%lld %lld\n", ans.m[0][0], ans.m[0][1]);
}
}
}