今天给大家分享一下一个朋友买的实战项目包，这个朋友呢跟大部分在座的一样，大学时就是天天打游戏泡酒吧，技术那是完全拉垮，虽说校招前恶补了两个月理论知识，但项目实战经验为零啊，这就好像某些人恋爱理论一套一套的，但你要问他谈过几个女朋友，他能跟你急眼，别问，问就是处男。强调一下真的是朋友，不是我[doge]。
这种情况下显然是找不到满意的工作的，没辙啊，我这位朋友又只能恶补项目实战，网上找了许久，今天跟我说这个看起来还不错，于是先花328买了一个小项目包，我们来看看这个项目有哪些东西。
篇幅所限，只给大家贴出部分源码，感兴趣的朋友可以点赞评论【项目实战】或者进群973961276即可获得所有源码跟电子书哦！
项目实战相关的视频资料我放在这里了☞c/c++ 项目实战，学习方法在这里☞企业级项目实战，三个月快速就业！
一、C和指针资料
这个文件夹里主要有一本叫《C和指针》的电子书和一些源码，其他一些零碎就不表了，我在下面贴一些电子书的截图和部分源码给大家看看。
《C和指针》☟
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《C和指针源代码及答案》☟
rearrang
/*
** This program reads input lines from the standard input and prints
** each input line, followed by just some portions of the lines, to
** the standard output.
**
** The first input is a list of column numbers, which ends with a
** negative number. The column numbers are paired and specify
** ranges of columns from the input line that are to be printed.
** For example, 0 3 10 12 -1 indicates that only columns 0 through 3
** and columns 10 through 12 will be printed.
*/
#include
#include
#include
#define MAX_COLS 20 /* max # of columns to process */
#define MAX_INPUT 1000 /* max len of input & output lines */
int read_column_numbers( int columns[], int max );
void rearrange( char *output, char const *input,
int n_columns, int const columns[] );
int
main( void )
{
int n_columns; /* # of columns to process */
int columns[MAX_COLS]; /* the columns to process */
char input[MAX_INPUT]; /* array for input line */
char output[MAX_INPUT]; /* array for output line */
/*
** Read the list of column numbers
*/
n_columns = read_column_numbers( columns, MAX_COLS );
/*
** Read, process and print the remaining lines of input.
*/
while( gets( input ) != NULL ){
printf( "Original input : %sn", input );
rearrange( output, input, n_columns, columns );
printf( "Rearranged line: %sn", output );
}
return EXIT_SUCCESS;
}
/*
** Read the list of column numbers, ignoring any beyond the specified
** maximum.
*/
int
read_column_numbers( int columns[], int max )
{
int num = 0;
int ch;
/*
** Get the numbers, stopping at eof or when a number is < 0.
*/
while( num < max && scanf( "%d", &columns[num] ) == 1
&& columns[num] >= 0 )
num += 1;
/*
** Make sure we have an even number of inputs, as they are
** supposed to be paired.
*/
if( num % 2 != 0 ){
puts( "Last column number is not paired." );
exit( EXIT_FAILURE );
}
/*
** Discard the rest of the line that contained the final
** number.
*/
while( (ch = getchar()) != EOF && ch != 'n' )
;
return num;
}
/*
** Process a line of input by concatenating the characters from
** the indicated columns. The output line is then NUL terminated.
*/
void
rearrange( char *output, char const *input,
int n_columns, int const columns[] )
{
int col; /* subscript for columns array */
int output_col; /* output column counter */
int len; /* length of input line */
len = strlen( input );
output_col = 0;
/*
** Process each pair of column numbers.
*/
for( col = 0; col < n_columns; col += 2 ){
int nchars = columns[col + 1] - columns[col] + 1;
/*
** If the input line isn't this long or the output
** array is full, we're done.
*/
if( columns[col] >= len ||
output_col == MAX_INPUT - 1 )
break;
/*
** If there isn't room in the output array, only copy
** what will fit.
*/
if( output_col + nchars > MAX_INPUT - 1 )
nchars = MAX_INPUT - output_col - 1;
/*
** Copy the relevant data.
*/
strncpy( output + output_col, input + columns[col],
nchars );
output_col += nchars;
}
output[output_col] = '0';
} s_srch1
/*
** Given a pointer to a NULL-terminated list of pointers, search
** the strings in the list for a particular character.
*/
#include
#define TRUE 1
#define FALSE 0
int
find_char( char **strings, char value )
{
char *string; /* the string we're looking at */
/*
** For each string in the list ...
*/
while( ( string = *strings++ ) != NULL ){
/*
** Look at each character in the string to see if
** it is the one we want.
*/
while( *string != '0' ){
if( *string++ == value )
return TRUE;
}
}
return FALSE;
} 二、WEB外挂
这个文件夹里面同样是有《外挂制作教程》和配套的电子书。一起来看看
外挂制作教程☟
《网络游戏外挂》☟
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三、Windows程序设计
Windows程序开发指南☟
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code☟
四、数据结构
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大概就是这些东西了，剩下的几个项目和配套电子书如果有人看的话再更新一下吧，点个赞让我知道有人在看好吗