175. 组合两个表

 SQL架构 

Create table Person (PersonId int, FirstName varchar(255), LastName varchar(255))
Create table Address (AddressId int, PersonId int, City varchar(255), State varchar(255))
Truncate table Person
insert into Person (PersonId, LastName, FirstName) values ('1', 'Wang', 'Allen')
Truncate table Address
insert into Address (AddressId, PersonId, City, State) values ('1', '2', 'New York City', 'New York')

表1: Person

+-------------+---------+
| 列名         | 类型     |
+-------------+---------+
| PersonId    | int     |
| FirstName   | varchar |
| LastName    | varchar |
+-------------+---------+
PersonId 是上表主键
表2: Address

+-------------+---------+
| 列名         | 类型    |
+-------------+---------+
| AddressId   | int     |
| PersonId    | int     |
| City        | varchar |
| State       | varchar |
+-------------+---------+
AddressId 是上表主键
 

编写一个 SQL 查询，满足条件：无论 person 是否有地址信息，都需要基于上述两表提供 person 的以下信息：

FirstName, LastName, City, State

SQL语句

# Write your MySQL query statement below
select p.FirstName,p.LastName,a.City,a.State
from
person p left join address a
on
p.personid=a.personid

 

来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/combine-two-tables
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